ELECTRICITY FOR TRADES (LOOSELEAF)
3rd Edition
ISBN: 9781260437454
Author: Petruzella
Publisher: MCG
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Chapter 6.1, Problem 19RQ
What is the advantage of taking a current reading with a DMM current probe?
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Question 3 AC Motor Drives [15]Calculate the instantaneous currents delivered by the inverter if the direct axiscurrent required at a particular instant is 8.66A and the quadrature current is5A. Derive all equations for the three currents.
A certain signal f(t) has the following PSD (assume 12 load):
Sp (w) = new + 8(w) - 1.5) + (w + 1.5)]
(a) What is the mean power in the bandwidth w≤2 rad/see?
(b) What is the mean power in the bandwidth -1.9 to 0.99 rad/sec?
Paress(w) dw
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Chapter 6 Solutions
ELECTRICITY FOR TRADES (LOOSELEAF)
Ch. 6.1 - Explain how measurements are made using an analog...Ch. 6.1 - Prob. 2RQCh. 6.1 - Name the three basic metering functions that can...Ch. 6.1 - What is the purpose of the multimeter function...Ch. 6.1 - What is the purpose of the multimeter range...Ch. 6.1 - An analog voltmeter uses a single scale calibrated...Ch. 6.1 - Unlike analog multimeters, digital multimeters...Ch. 6.1 - Prob. 8RQCh. 6.1 - How are voltmeters connected relative to the...Ch. 6.1 - Digital voltmeters have little or no loading...
Ch. 6.1 - A digital multimeter is used to measure a DC...Ch. 6.1 - Define voltage drop.Ch. 6.1 - How are ground-referenced voltage measurements...Ch. 6.1 - State one advantage and one limitation of a...Ch. 6.1 - A noncontact voltage detector is to be used to...Ch. 6.1 - When measuring voltages and currents of unknown...Ch. 6.1 - How must ammeters be connected relative to the...Ch. 6.1 - Ammeters are required to have very low resistance...Ch. 6.1 - What is the advantage of taking a current reading...Ch. 6.1 - Explain how a clamp-on ammeter measures current...Ch. 6.1 - While attempting a voltage measurement across a...Ch. 6.1 - A clamp-on ammeter is to be used to determine the...Ch. 6.2 - What four basic components make up the internal...Ch. 6.2 - How is the pointer of an analog-type ohmmeter set...Ch. 6.2 - Series analog ohmmeters have nonlinear scales....Ch. 6.2 - What does a resistance reading of OL on a digital...Ch. 6.2 - A multimeter set to measure resistance is...Ch. 6.2 - When doing in-circuit component resistance...Ch. 6.2 - Explain the purpose of the multimeter continuity...Ch. 6.2 - An ohmmeter is connected across the two leads of a...Ch. 6.2 - Convert each of the following digital multimeter...Ch. 6.2 - Give an example of what might cause the occurrence...Ch. 6.2 - What energy-level category of multimeter is...Ch. 6.2 - A simple resistance measurement is made to test...Ch. 6.2 - What type of hand protection may be required when...Ch. 6.2 - Compare the input impedance of analog and digital...Ch. 6.2 - Define meter accuracy.Ch. 6.2 - Define meter resolution.Ch. 6.2 - What protection is afforded by the fuse connected...Ch. 6.2 - Prob. 18RQCh. 6.2 - The diode test function of a DMM is to be used to...Ch. 6.2 - Under what condition will true RMS and averaging...
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- (75 Marks) JA signal (t) is bond 7)(t)(t) and f(t), are band-limited to 1.2 kHz each. These signals are to be limited to 9.6 kHz, and three other signals transmitted by means of time-division multiplexing. Set up scheme for accomplishing this multiplexing requirement, with each signal sampled at its Nyquist rate. What must be the speed of the commutator (the output but ram-k bit/sec)? the minimum band width? (25 Marks)arrow_forwardDraw the digital modulation outputs, ASK Amplitude Shift Keying) FSK (Frequency Shift Keying) and PSK (Phase Shift Keying). For baseband and carriet frequency as shown 101 wwwwwwwwwwww 010 BASESAND basband CARRIER Carralarrow_forwardplease show full working. I've included the solutionarrow_forward
- can you please show working and steps. The answer is 8kohms.arrow_forwardPSD A certain signal f(t) has the following PSD (assume 12 load): | Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)] (a) What is the mean power in the bandwidth w≤ 1 rad/sec? (b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec? (c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec? (d) What is the total mean power in (t)? Pav= + 2T SfLw) dw - SALW)arrow_forwardAn AM modulation waveform signal:- p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt (a) Sketch the amplitude spectrum of p(t). (b) Find total power, sideband power and power efficiency. (c) Find the average power containing of each sideband.arrow_forward
- Can you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forward
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