The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Concept explainers
Question
Chapter 6.1, Problem 11E
To determine
To find: The mean of the random variable X and interpret it
Expert Solution & Answer
Answer to Problem 11E
The mean is 2.1.
Explanation of Solution
Given:
The probability distribution is:
Value of X | 0 | 1 | 2 | 3 | 4 |
Probability | 0.1 | 0.2 | 0.3 | 0.3 | 0.1 |
Formula used:
The formula to compute the mean is:
Calculation:
The mean can be calculated as:
Interpretation:
The expected number of nonword error in the essay that has 250 words are 2.1.
Chapter 6 Solutions
The Practice of Statistics for AP - 4th Edition
Ch. 6.1 - Prob. 1.1CYUCh. 6.1 - Prob. 1.2CYUCh. 6.1 - Prob. 1.3CYUCh. 6.1 - Prob. 2.1CYUCh. 6.1 - Prob. 2.2CYUCh. 6.1 - Prob. 1ECh. 6.1 - Prob. 2ECh. 6.1 - Prob. 3ECh. 6.1 - Prob. 4ECh. 6.1 - Prob. 5E
Ch. 6.1 - Prob. 6ECh. 6.1 - Prob. 7ECh. 6.1 - Prob. 8ECh. 6.1 - Prob. 9ECh. 6.1 - Prob. 10ECh. 6.1 - Prob. 11ECh. 6.1 - Prob. 12ECh. 6.1 - Prob. 13ECh. 6.1 - Prob. 14ECh. 6.1 - Prob. 15ECh. 6.1 - Prob. 16ECh. 6.1 - Prob. 17ECh. 6.1 - Prob. 18ECh. 6.1 - Prob. 19ECh. 6.1 - Prob. 20ECh. 6.1 - Prob. 21ECh. 6.1 - Prob. 22ECh. 6.1 - Prob. 23ECh. 6.1 - Prob. 24ECh. 6.1 - Prob. 25ECh. 6.1 - Prob. 26ECh. 6.1 - Prob. 27ECh. 6.1 - Prob. 28ECh. 6.1 - Prob. 29ECh. 6.1 - Prob. 30ECh. 6.1 - Prob. 31ECh. 6.1 - Prob. 32ECh. 6.1 - Prob. 33ECh. 6.1 - Prob. 34ECh. 6.2 - Prob. 1.1CYUCh. 6.2 - Prob. 1.2CYUCh. 6.2 - Prob. 2.1CYUCh. 6.2 - Prob. 2.2CYUCh. 6.2 - Prob. 2.3CYUCh. 6.2 - Prob. 3.1CYUCh. 6.2 - Prob. 3.2CYUCh. 6.2 - Prob. 3.3CYUCh. 6.2 - Prob. 35ECh. 6.2 - Prob. 36ECh. 6.2 - Prob. 37ECh. 6.2 - Prob. 38ECh. 6.2 - Prob. 39ECh. 6.2 - Prob. 40ECh. 6.2 - Prob. 41ECh. 6.2 - Prob. 42ECh. 6.2 - Prob. 43ECh. 6.2 - Prob. 44ECh. 6.2 - Prob. 45ECh. 6.2 - Prob. 46ECh. 6.2 - Prob. 47ECh. 6.2 - Prob. 48ECh. 6.2 - Prob. 49ECh. 6.2 - Prob. 50ECh. 6.2 - Prob. 51ECh. 6.2 - Prob. 52ECh. 6.2 - Prob. 53ECh. 6.2 - Prob. 54ECh. 6.2 - Prob. 55ECh. 6.2 - Prob. 56ECh. 6.2 - Prob. 57ECh. 6.2 - Prob. 58ECh. 6.2 - Prob. 59ECh. 6.2 - Prob. 60ECh. 6.2 - Prob. 61ECh. 6.2 - Prob. 62ECh. 6.2 - Prob. 63ECh. 6.2 - Prob. 64ECh. 6.2 - Prob. 65ECh. 6.2 - Prob. 66ECh. 6.2 - Prob. 67ECh. 6.2 - Prob. 68ECh. 6.3 - Prob. 1.1CYUCh. 6.3 - Prob. 1.2CYUCh. 6.3 - Prob. 1.3CYUCh. 6.3 - Prob. 2.1CYUCh. 6.3 - Prob. 2.2CYUCh. 6.3 - Prob. 2.3CYUCh. 6.3 - Prob. 3.1CYUCh. 6.3 - Prob. 3.2CYUCh. 6.3 - Prob. 3.3CYUCh. 6.3 - Prob. 4.1CYUCh. 6.3 - Prob. 4.2CYUCh. 6.3 - Prob. 4.3CYUCh. 6.3 - Prob. 69ECh. 6.3 - Prob. 70ECh. 6.3 - Prob. 71ECh. 6.3 - Prob. 72ECh. 6.3 - Prob. 73ECh. 6.3 - Prob. 74ECh. 6.3 - Prob. 75ECh. 6.3 - Prob. 76ECh. 6.3 - Prob. 77ECh. 6.3 - Prob. 78ECh. 6.3 - Prob. 79ECh. 6.3 - Prob. 80ECh. 6.3 - Prob. 81ECh. 6.3 - Prob. 82ECh. 6.3 - Prob. 83ECh. 6.3 - Prob. 84ECh. 6.3 - Prob. 85ECh. 6.3 - Prob. 86ECh. 6.3 - Prob. 87ECh. 6.3 - Prob. 88ECh. 6.3 - Prob. 89ECh. 6.3 - Prob. 90ECh. 6.3 - Prob. 91ECh. 6.3 - Prob. 92ECh. 6.3 - Prob. 93ECh. 6.3 - Prob. 94ECh. 6.3 - Prob. 95ECh. 6.3 - Prob. 96ECh. 6.3 - Prob. 97ECh. 6.3 - Prob. 98ECh. 6.3 - Prob. 99ECh. 6.3 - Prob. 100ECh. 6.3 - Prob. 101ECh. 6.3 - Prob. 102ECh. 6.3 - Prob. 103ECh. 6.3 - Prob. 104ECh. 6.3 - Prob. 105ECh. 6.3 - Prob. 106ECh. 6.3 - Prob. 107ECh. 6 - Prob. 1CRECh. 6 - Prob. 2CRECh. 6 - Prob. 3CRECh. 6 - Prob. 4CRECh. 6 - Prob. 5CRECh. 6 - Prob. 6CRECh. 6 - Prob. 7CRECh. 6 - Prob. 8CRECh. 6 - Prob. 1PTCh. 6 - Prob. 2PTCh. 6 - Prob. 3PTCh. 6 - Prob. 4PTCh. 6 - Prob. 5PTCh. 6 - Prob. 6PTCh. 6 - Prob. 7PTCh. 6 - Prob. 8PTCh. 6 - Prob. 9PTCh. 6 - Prob. 10PTCh. 6 - Prob. 11PTCh. 6 - Prob. 12PTCh. 6 - Prob. 13PTCh. 6 - Prob. 14PT
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