Finding binary numbers from 1 through 10: Numbers Binary numbers 1 0000 0001 2 0000 0010 3 0000 0011

Question

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Answer 1

Expert Solution & Answer

Chapter 6, Problem P4P

a.

Explanation of Solution

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

b.

Explanation of Solution

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

c.

Explanation of Solution

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100

d.

Explanation of Solution

Steps to find internet checksum:

Step 1: Find ASCII value for the string.

Step 2: Find 8-bit binary number for the corresponding ASCII values.

Step 3: Add 16-bit numbers. If carry occurs, then wrap that around.

Step 4: Take 1’s complement for the final result to find out internet checksum.

For part (a) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result doesn’t produce carry and therefore take 1’s complement.

1’s complement for “0001 1001 0001 1110” is “1110 0110 1110 0001”.

Therefore, internet checksum for the numbers 1 through 10 is “1110 0110 1110 0001”.

For part (b) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result produces carry bit so carry forward it.

Now, take 1’s complement. 1’s complement for “0101 1111 0110 0100” is “1010 0000 1001 1011”.

Therefore, internet checksum for the letters “B” through “K” is “1010 0000 1001 1011”...

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write a simple memory management simulator in C that supports paging. In this setup the logical address space (216= 65,536 bytes) is larger than the physical address space (215 bytes), and the page size is 256 bytes. The maximum no. of entries in the TLB (Translation Lookaside Buffer) = 16. memory.c - You are to provide your solution in a single C program named memory.c. Your simulator needs to accomplish the following: 1. Simulate a memory management unit (MMU), which translates logical addresses to physical addresses 1. Translating a logical address to physical address in this setup will involve the following: Check TLB for the page. If page not found in the TLB, check the page table if the page exists in memory. If it does not, then a page fault occurs. 2. Handling page faults involves copy the page from the backing store to memory. Since logical address space is larger than physical address space, a page request might involve replacing a page in memory with the new page. The page…

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Answer 2

Expert Solution & Answer

Chapter 6, Problem P4P

a.

Explanation of Solution

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

b.

Explanation of Solution

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

c.

Explanation of Solution

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100

d.

Explanation of Solution

Steps to find internet checksum:

Step 1: Find ASCII value for the string.

Step 2: Find 8-bit binary number for the corresponding ASCII values.

Step 3: Add 16-bit numbers. If carry occurs, then wrap that around.

Step 4: Take 1’s complement for the final result to find out internet checksum.

For part (a) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result doesn’t produce carry and therefore take 1’s complement.

1’s complement for “0001 1001 0001 1110” is “1110 0110 1110 0001”.

Therefore, internet checksum for the numbers 1 through 10 is “1110 0110 1110 0001”.

For part (b) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result produces carry bit so carry forward it.

Now, take 1’s complement. 1’s complement for “0101 1111 0110 0100” is “1010 0000 1001 1011”.

Therefore, internet checksum for the letters “B” through “K” is “1010 0000 1001 1011”...

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Expert Solution & Answer

Chapter 6, Problem P4P

a.

Explanation of Solution

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

b.

Explanation of Solution

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

c.

Explanation of Solution

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100

d.

Explanation of Solution

Steps to find internet checksum:

Step 1: Find ASCII value for the string.

Step 2: Find 8-bit binary number for the corresponding ASCII values.

Step 3: Add 16-bit numbers. If carry occurs, then wrap that around.

Step 4: Take 1’s complement for the final result to find out internet checksum.

For part (a) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result doesn’t produce carry and therefore take 1’s complement.

1’s complement for “0001 1001 0001 1110” is “1110 0110 1110 0001”.

Therefore, internet checksum for the numbers 1 through 10 is “1110 0110 1110 0001”.

For part (b) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result produces carry bit so carry forward it.

Now, take 1’s complement. 1’s complement for “0101 1111 0110 0100” is “1010 0000 1001 1011”.

Therefore, internet checksum for the letters “B” through “K” is “1010 0000 1001 1011”...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 6, Problem P4P

a.

Explanation of Solution

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

b.

Explanation of Solution

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

c.

Explanation of Solution

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100

d.

Explanation of Solution

Steps to find internet checksum:

Step 1: Find ASCII value for the string.

Step 2: Find 8-bit binary number for the corresponding ASCII values.

Step 3: Add 16-bit numbers. If carry occurs, then wrap that around.

Step 4: Take 1’s complement for the final result to find out internet checksum.

For part (a) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result doesn’t produce carry and therefore take 1’s complement.

1’s complement for “0001 1001 0001 1110” is “1110 0110 1110 0001”.

Therefore, internet checksum for the numbers 1 through 10 is “1110 0110 1110 0001”.

For part (b) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result produces carry bit so carry forward it.

Now, take 1’s complement. 1’s complement for “0101 1111 0110 0100” is “1010 0000 1001 1011”.

Therefore, internet checksum for the letters “B” through “K” is “1010 0000 1001 1011”...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 6, Problem P4P

a.

Explanation of Solution

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

b.

Explanation of Solution

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

c.

Explanation of Solution

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100

d.

Explanation of Solution

Steps to find internet checksum:

Step 1: Find ASCII value for the string.

Step 2: Find 8-bit binary number for the corresponding ASCII values.

Step 3: Add 16-bit numbers. If carry occurs, then wrap that around.

Step 4: Take 1’s complement for the final result to find out internet checksum.

For part (a) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result doesn’t produce carry and therefore take 1’s complement.

1’s complement for “0001 1001 0001 1110” is “1110 0110 1110 0001”.

Therefore, internet checksum for the numbers 1 through 10 is “1110 0110 1110 0001”.

For part (b) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result produces carry bit so carry forward it.

Now, take 1’s complement. 1’s complement for “0101 1111 0110 0100” is “1010 0000 1001 1011”.

Therefore, internet checksum for the letters “B” through “K” is “1010 0000 1001 1011”...

Answer 8

Chapter 6, Problem P4P

a.

Explanation of Solution

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

Answer 9

Chapter 6, Problem P4P

a.

Explanation of Solution

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

Answer 10

b.

Explanation of Solution

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

Answer 11

b.

Explanation of Solution

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

Answer 12

c.

Explanation of Solution

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100

Answer 13

c.

Explanation of Solution

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100

Answer 14

d.

Explanation of Solution

Steps to find internet checksum:

Step 1: Find ASCII value for the string.

Step 2: Find 8-bit binary number for the corresponding ASCII values.

Step 3: Add 16-bit numbers. If carry occurs, then wrap that around.

Step 4: Take 1’s complement for the final result to find out internet checksum.

For part (a) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result doesn’t produce carry and therefore take 1’s complement.

1’s complement for “0001 1001 0001 1110” is “1110 0110 1110 0001”.

Therefore, internet checksum for the numbers 1 through 10 is “1110 0110 1110 0001”.

For part (b) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result produces carry bit so carry forward it.

Now, take 1’s complement. 1’s complement for “0101 1111 0110 0100” is “1010 0000 1001 1011”.

Therefore, internet checksum for the letters “B” through “K” is “1010 0000 1001 1011”...

Answer 15

d.

Explanation of Solution

Steps to find internet checksum:

Step 1: Find ASCII value for the string.

Step 2: Find 8-bit binary number for the corresponding ASCII values.

Step 3: Add 16-bit numbers. If carry occurs, then wrap that around.

Step 4: Take 1’s complement for the final result to find out internet checksum.

For part (a) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result doesn’t produce carry and therefore take 1’s complement.

1’s complement for “0001 1001 0001 1110” is “1110 0110 1110 0001”.

Therefore, internet checksum for the numbers 1 through 10 is “1110 0110 1110 0001”.

For part (b) the internet checksum is calculated as follows:

Add all the 16-bit integers:

The above result produces carry bit so carry forward it.

Now, take 1’s complement. 1’s complement for “0101 1111 0110 0100” is “1010 0000 1001 1011”.

Therefore, internet checksum for the letters “B” through “K” is “1010 0000 1001 1011”...

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

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Answer 19

Ch. 6 - Consider the transportation analogy in Section...Ch. 6 - If all the links in the Internet were to provide...Ch. 6 - Prob. R3RQ Ch. 6 - Prob. R4RQ Ch. 6 - Prob. R5RQ Ch. 6 - Prob. R6RQ Ch. 6 - Prob. R7RQ Ch. 6 - Prob. R8RQ Ch. 6 - Prob. R9RQ Ch. 6 - Prob. R10RQ

Finding binary numbers from 1 through 10: Numbers Binary numbers 1 0000 0001 2 0000 0010 3 0000 0011

Solution Summary: The author explains how to find the internet checksum.

Explanation of Solution

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

Explanation of Solution

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

Explanation of Solution

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100

Explanation of Solution

Want to see the full answer?

Chapter 6 Solutions

Letters	ASCII values	Binary number
B	66	0100 0010
C	67	0100 0011
D	68	0100 0100

Finding binary numbers from 1 through 10: Numbers Binary numbers 1 0000 0001 2 0000 0010 3 0000 0011

Solution Summary: The author explains how to find the internet checksum.

Explanation of Solution

Finding binary numbers from 1 through 10: NumbersBinary numbers10000 000120000 001030000 0011

Explanation of Solution

ASCII values for the letters from “B” through “K”: LettersASCII valuesBinary numberB660100 0010C670100 0011D680100 0100

Explanation of Solution

ASCII values for the letters from “b” through “k”: LettersASCII valuesBinary numberb980110 0010c990110 0011d1000110 0100

Explanation of Solution

Want to see the full answer?

Chapter 6 Solutions

Finding binary numbers from 1 through 10:

Numbers Binary numbers
1 0000 0001
2 0000 0010
3 0000 0011

ASCII values for the letters from “B” through “K”:

Letters ASCII values Binary number
B 66 0100 0010
C 67 0100 0011
D 68 0100 0100

ASCII values for the letters from “b” through “k”:

Letters ASCII values Binary number
b 98 0110 0010
c 99 0110 0011
d 100 0110 0100