Chapter 6, Problem P27P

a.

Explanation of Solution

Given:

• Consider that the packet for Voice-over-IP contains p bytes and 5 bytes of header.
• The source is encoded at the rate of 128 kbps.

To Find: Packetization delay (in milliseconds).

Solution:

The time needed to fill (L * 8) bits are:

b.

Explanation of Solution

Given:

• Consider that the packet for Voice-over-IP contains p bytes and 5 bytes of header.

To Find:

• Packetization delay for L = 1500 bytes (in milliseconds).
• Packetization delay for L = 50 bytes (in milliseconds).

Solution:

The formula to find Packetization is: $\frac{\text{L}}{16}\text{ msec}$

For $L=1500bytes$:

Packetization delay for $\text{L = 1500 bytes}$ is:

$\begin{array}{l}\text{Packetization delay = }\frac{\text{L}}{16}\text{ msec}\\ =>\frac{1500}{16}\text{ msec}\\ \text{=> 93}\text{.75 msec}\end{array}$

Therefore, the Packetization delay is: $93$

c.

Explanation of Solution

Given:

• Consider that the packet for Voice-over-IP contains p bytes and 5 bytes of header.
• The source is encoded at the rate of 128 kbps.
• Link Rate (R) = 622 Mbps for L = 1500 bytes and L = 50 bytes.

To Find: Store-and-forward delay

Solution:

The formula to find store-and-forward delay is $\frac{\text{L }\times \text{ 8 + 40}}{\text{R}}$

For $L=1500bytes$:

Store-and-forward delay for $\text{L = 1500 bytes}$ is:

$\begin{array}{l}\text{Store-and-forward delay = }\frac{\text{L * 8 + 40}}{\text{R}}\\ =>\frac{(1500*8)+40}{622*{10}^6}\text{ sec}\\ \text{=> 19}\text{.4μsec}\end{array}$

Therefore, the store-and-forward delay is: $19$

d.

Explanation of Solution

Advantage of using small packet size:

By using the smal...