
Concept explainers
(a)
To determine: The substrate concentration at which an enzyme with a Kcat of 30.0s-1 and Km of 0.0050M operate at one-quarter of its maximum rate.
Introduction:
Kcat is defined as a constant that is used to describe turnover rate of enzyme-substrate complex into product and enzyme. It is a turnover number of an enzyme which is used to indicate the conversion of maximum number of substrate into product per active site per unit time.
(a)

Explanation of Solution
Explanation:
The formula for calculating concentration of substrate
The values for Kcat, Km and V are substituted in the formula for calculating concentration of substrate,
Conclusion:
The concentration of substrate is
(b)
To determine: The fraction of Vmax which is obtained at following substrate concentrations
Introduction:
Enzyme kinetics is defined as the study of
(b)

Explanation of Solution
Explanation:
The formula for calculating fractions of Vmax at different substrate concentrations is,
Substituting the value of
Substituting the value of
Substituting the value of
Conclusion:
The fractions of Vmax at different substrate concentration is 0.33, 0.66 and 0.90.
(c)
To determine: The different curves corresponds to which enzyme.
Introduction:
Enzyme is a biological macromolecule that acts as a catalyst and enhance rate of chemical reactions. Various biological processes are dependent on enzyme. All enzymes have an active site on to which amino acids of proteins get binds and form an enzyme-substrate complex.
(c)

Explanation of Solution
Explanation:
The upper curve indicates enzyme B as [X] is greater than Km of enzyme while lower curve indicates enzyme A as the [X] is smaller than Km of enzyme.
It can be concluded that if the rate of initial concentration of substrate is greater than
Conclusion:
In the given graph, upper curve corresponds to enzyme B whereas lower curve corresponds to enzyme A.
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Chapter 6 Solutions
Lehninger Principles of Biochemistry
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