Males’ Body Temperatures A study of human body temperatures using healthy men showed a mean of 98.1 ∘ F and a standard deviation of 0.70. ∘ F Assume the temperatures are approximately normally distributed. a. Find the percentage of healthy men with temperatures below 98.6 ° F (that temperature was considered typical for many decades). b. What temperature does a healthy man have if his temperature is at the 76th percentile?
Males’ Body Temperatures A study of human body temperatures using healthy men showed a mean of 98.1 ∘ F and a standard deviation of 0.70. ∘ F Assume the temperatures are approximately normally distributed. a. Find the percentage of healthy men with temperatures below 98.6 ° F (that temperature was considered typical for many decades). b. What temperature does a healthy man have if his temperature is at the 76th percentile?
Solution Summary: The author calculates the percentage of healthy men with a body temperature below 98.6circF based on the normal distribution and the standard deviation.
Males’ Body Temperatures A study of human body temperatures using healthy men showed a mean of
98.1
∘
F
and a standard deviation of
0.70.
∘
F
Assume the temperatures are approximately normally distributed.
a. Find the percentage of healthy men with temperatures below
98.6
°
F
(that temperature was considered typical for many decades).
b. What temperature does a healthy man have if his temperature is at the 76th percentile?
Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.
The masses measured on a population of 100 animals were grouped in the
following table, after being recorded to the nearest gram
Mass
89 90-109 110-129 130-149 150-169 170-189 > 190
Frequency 3
7 34
43
10
2
1
You are given that the sample mean of the data is 131.5 and the sample
standard deviation is 20.0. Test the hypothesis that the distribution of masses
follows a normal distribution at the 5% significance level.
state without proof
the uniqueness
theorm of probability
function
(a+b)
R2L
2+2*0=?
Ma
state without proof the uniqueness theorm
of probability function suppose thatPandQ
are probability measures defined on the
same probability space (Q, F)and that
Fis generated by a π-system if P(A)=Q(A)
tax for all A EthenP=Q i. e. P(A)=Q(A) for alla g
// معدلة 2:23 ص
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Hypothesis Testing using Confidence Interval Approach; Author: BUM2413 Applied Statistics UMP;https://www.youtube.com/watch?v=Hq1l3e9pLyY;License: Standard YouTube License, CC-BY
Hypothesis Testing - Difference of Two Means - Student's -Distribution & Normal Distribution; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=UcZwyzwWU7o;License: Standard Youtube License