Equal area property for parabolas Let f ( x ) = ax 2 + bx + c be an arbitrary quadratic function and choose two points x = p and x= q . Let L 1 be the line tangent to the graph of f at the point ( p , f ( p )) and let L 2 be the line tangent to the graph at the point ( q , f ( q )). Let x = s be the vertical line through the intersection point of L 1 and L 2 . Finally, let R 1 , be the region bounded by y = f ( x ), L 1 , and the vertical line x = s , and let R 2 be the region bounded by y = f ( x ), L 2 , and the vertical line x = s . Prove that the area of R 1 equals the area of R 2 .
Equal area property for parabolas Let f ( x ) = ax 2 + bx + c be an arbitrary quadratic function and choose two points x = p and x= q . Let L 1 be the line tangent to the graph of f at the point ( p , f ( p )) and let L 2 be the line tangent to the graph at the point ( q , f ( q )). Let x = s be the vertical line through the intersection point of L 1 and L 2 . Finally, let R 1 , be the region bounded by y = f ( x ), L 1 , and the vertical line x = s , and let R 2 be the region bounded by y = f ( x ), L 2 , and the vertical line x = s . Prove that the area of R 1 equals the area of R 2 .
Solution Summary: The author explains that the area of R_1 is equal to the amount of the value of a quadratic function.
Equal area property for parabolas Let f(x) = ax2 + bx + c be an arbitrary quadratic function and choose two points x = p and x= q. Let L1 be the line tangent to the graph of f at the point (p, f(p)) and let L2 be the line tangent to the graph at the point (q, f(q)). Let x = s be the vertical line through the intersection point of L1 and L2. Finally, let R1, be the region bounded by y =f(x), L1, and the vertical line x = s, and let R2 be the region bounded by y = f(x), L2, and the vertical line x = s. Prove that the area of R1 equals the area of R2.
1- √ √ √³ e³/√xdy dx
1 cy²
2- √ √² 3 y³ exy dx dy
So
3- √ √sinx y dy dx
4-
Jo
√² Sy² dx dy
A building that is 205 feet tall casts a shadow of various lengths æ as the day goes by. An angle of
elevation is formed by lines from the top and bottom of the building to the tip of the shadow, as
de
seen in the following figure. Find the rate of change of the angle of elevation when x 278 feet.
dx
Round to 3 decimal places.
Γ
X
radians per foot
Use the information in the following table to find h' (a) at the given value for a.
x|f(x) g(x) f'(x) g(x)
0
0
0
4
3
1
4
4
3
0
2
7
1
2
7
3
3
1
2
9
4
0
4
5
7
h(x) = f(g(x)); a = 0
h' (0) =
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