Explanation The part a can be calculated from energy conservation equation and the part b can be solved from projectile motion consideration. Given The mass of the skier is m = 55 kg . The vertical height from A is 45 .0 m . The point b is at a height of, h = 45.0 − 4.4 m h = 40.6 m Formula used For v B calculation, from energy conservation, the equation to be used is 1 2 m v B 2 = m g h . To calculate the distance s, take into consideration projectile motion. Second equation of motion: s = u t + 1 2 a t 2 Where, u is the initial speed, a is the acceleration, s is the displacement and t is the time. Calculations: Part a 1 2 m v B 2 = m g h v B 2 = 2 g h v B = 2 × 9.8 × 40.6 m s v B = 28.2 m s Part b The horizontal distance moved by the skier is: s cos 30 ° = 28

7th Edition

ISBN: 2818440037979

Author: GIANCOLI

Publisher: PEARSON

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Chapter 6, Problem 86GP

To determine

a. The speed vB when the skier reaches the point B.

b. The distance s.

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Chapter 6, Problem 85GP

Chapter 6, Problem 87GP

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a. The speed v B when the skier reaches the point B. b. The distance s.