Chapter 6, Problem 82E

Interpretation Introduction

Interpretation:

The molar mass of gas should be calculatedwhichneeds 64 s to effuse under similar conditions of ${\text{N}}_{\text{2}}$ gas.

Concept introduction:

According to the Graham’s law of effusion, rate of effusion of any gas is always inversely proportional to the square root of the mass of gaseous particles.

The mathematical expression for this law is:

$\frac{\text{Rate of effusion of gas 1}}{\text{Rate of effusion of gas 2}}\text{=}\sqrt{\frac{\text{M2}}{\text{M1}}}$

In terms of time for gases; expression is written as:

$\frac{\text{Effusion time of gas 1}}{\text{Effusion time of gas 2}}\text{=}\sqrt{\frac{\text{M1}}{\text{M2}}}$