The energy of any one-electron species in its nth state ( n = principal quantum number ) is given by E = − BZ 2 / n 2 , where Z is the charge on the nucleus and B is 2.180 × 10 − 18 J . Find the ionization energy of the Li 2 + ion in its first excited state in kilojoules per mole.
The energy of any one-electron species in its nth state ( n = principal quantum number ) is given by E = − BZ 2 / n 2 , where Z is the charge on the nucleus and B is 2.180 × 10 − 18 J . Find the ionization energy of the Li 2 + ion in its first excited state in kilojoules per mole.
Solution Summary: The author explains the ionization energy of Li 2 + ions in its first excited state. The ground state of energy is the minimum energy level an electron can occupy.
The energy of any one-electron species in its nth state
(
n
=
principal
quantum
number
)
is given by
E
=
−
BZ
2
/
n
2
, where Z is the charge on the nucleus and B is
2.180
×
10
−
18
J
. Find the ionization energy of the
Li
2
+
ion in its first excited state in kilojoules per mole.
Some of the theories used to describe interface structure can be distinguished by:1. the measured potential difference.2. the distribution of ions in solution.3. the calculation of charge density.4. the external Helmoltz plane.
When talking about the acidity of carboxylic acids, is it the same thing to say higher or stronger acidity?
Using the following two half-reactions, determine the pH range in which $NO_2^-\ (aq)$ cannot be found as the predominant chemical species in water.* $NO_3^-(aq)+10H^+(aq)+8e^-\rightarrow NH_4^+(aq)+3H_2O(l),\ pE^{\circ}=14.88$* $NO_2^-(aq)+8H^+(aq)+6e^-\rightarrow NH_4^+(aq)+2H_2O(l),\ pE^{\circ}=15.08$
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