Chapter 6, Problem 70A

Interpretation Introduction

Interpretation: The item in list B must be found that best explains or completes the statement or question in list A.

Concept Introduction :

Empirical formula of a molecule is the smallest unit which is repeated in the molecule.

Amu is known as atomic mass unit which is nearly the mass of 1 H atom.

1 mol of any substance contains Avogadro’s number $(6.023\times {10}^{23}).$ of fundamental particles.

Answer to Problem 70A

1 will match with g.

2 will match with c.

3 will match with b.

4 will match with a.

5 will match with j.

6 will match with i.

7 will match with f.

8 will match with h.

9 will match with e.

10 will match with d.

Explanation of Solution

1 will match with ‘g’ as 1 amu $\text{=}\frac{\text{1}}{\text{6}{\text{.023×10}}^{\text{23}}}\text{g=1}{\text{.66×10}}^{\text{-24}}\text{g}$ .

2 will match with ‘c’ as mass of 1 H atom is 1.008 amu. So 1000 H atoms will have mass $\text{=1000×1}\text{.008 amu=1008 amu}\text{.}$

3 will match with ‘b’ as mass of the “average” atom of an element is known as atomic mass.

4 will match with ‘a’ as 12.01 g C is 1 mol which must contain $6.023\times {10}^{23}$ number of C atoms.

5 will match with ‘j’ as 1 mol contains $6.023\times {10}^{23}$ of molecules.

6 will match with ‘i’ as total mass of all atoms in 1 mole substance is known as molar mass.

7 will match with ‘f’ as smallest whole number ratio of atoms is known as empirical formula.

8 will match with ‘h’ as formula which shows actual number of atoms in a molecule is molecular formula.

9 will match with ‘e’ as any carbon containing compound produces carbon dioxide after burning.

10 will match with ‘d’ as benzene (C₆H₆) and acetylene(C₂H₂) both have same empirical formula (C₂H₂) but different molecular formula of C₆H₆ and C₂H₂ respectively..