![World of Chemistry, 3rd edition](https://www.bartleby.com/isbn_cover_images/9781133109655/9781133109655_smallCoverImage.jpg)
Concept explainers
(a)
Interpretation:
The number of molecules present in the samples needs to be predicted.
Concept Introduction:
Mole is the amount of the substance that contains the same number of particles or atoms or molecules. Molar mass is defined as an average
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 26A
Number of molecules of CO in 6.37 mol = 3.836 ×1022 molecules
Explanation of Solution
Number of molecules in 6.37 mol of carbon monoxide
Number of carbon monoxide molecules = Number of moles ×
= 6.37 mol × (6.022140857 × 1023 molecules / mol)
= 38.361 × 1023 molecules
= 3.836 ×1022 molecules
(b)
Interpretation:
The number of molecules present in the samples needs to be predicted.
Concept Introduction:
Mole is the amount of the substance that contains the same number of particles or atoms or molecules. Molar mass is defined as an average mass of atoms present in the chemical formula. It is the sum of the atomic masses of all the atoms present in the chemical formula of any compound.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 26A
Number of molecules of CO in 6.37 g = 1.37 × 1023 molecules
Explanation of Solution
Number of molecules in 6.37 g carbon monoxide
Molecular formula = CO
Molecular mass = 28.01 g/ mol
Given,
Mass of CO = 6.37g
The calculation of moles is shown below:
Number of CO molecules = Number of moles × Avogadro number
= 0.227418779 mol × (6.022140857 × 1023 molecules / mol)
= 1.37 ×1023 molecules
(c)
Interpretation:
The number of molecules present in the samples needs to be predicted.
Concept Introduction:
Mole is the amount of the substance that contains the same number of particles or atoms or molecules. Molar mass is defined as an average mass of atoms present in the chemical formula. It is the sum of the atomic masses of all the atoms present in the chemical formula of any compound.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 26A
Number of molecules of H2O in 2.62 ×10-6 g = 8.76× 1016 molecules
Explanation of Solution
Number of molecules in 2.62×10-6 g water
Molecular formula = H2O
Molecular mass = 18g/ mol
Given,
Mass of H2O = 2.62×10-6 g
The calculation of moles is shown below:
Number of H2O molecules = Number of moles × Avogadro number
= 1.4555 ×10-7 mol × (6.022140857 × 1023 molecules / mol)
= 8.76 ×1016 molecules
(d)
Interpretation:
The number of molecules present in the samples needs to be predicted.
Concept Introduction:
Mole is the amount of the substance that contains the same number of particles or atoms or molecules. Molar mass is defined as an average mass of atoms present in the chemical formula. It is the sum of the atomic masses of all the atoms present in the chemical formula of any compound.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 26A
Number of molecules of H2O in 2.62× 10-6 mol = 1.58 ×1018 molecules
Explanation of Solution
Number of molecules in 2.62 × 10-6 mol of water
Number of water molecules = Number of moles × Avogadro number
= 2.62 × 10-6 mol × (6.022140857 × 1023 molecules / mol)
= 15.78 × 1017 molecules
= 1.58 ×1018 molecules
(e)
Interpretation:
The number of molecules present in the samples needs to be predicted.
Concept Introduction:
Mole is the amount of the substance that contains the same number of particles or atoms or molecules. Molar mass is defined as an average mass of atoms present in the chemical formula. It is the sum of the atomic masses of all the atoms present in the chemical formula of any compound.
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 26A
Number of molecules of C6H6 in 5.23 g = 4.029× 1022 molecules
Explanation of Solution
Number of molecules in 5.23 g benzene
Molecular formula = C6H6
Molecular mass = 78.11 g/ mol
Given,
Mass of C6H6= 5.23 g
The calculation of moles is shown below:
Number of C6H6 molecules = Number of moles × Avogadro number
= 0.0669 mol × (6.022140857 × 1023 molecules / mol)
= 4.029 ×1022 molecules
Chapter 6 Solutions
World of Chemistry, 3rd edition
- Carbohydrates- Draw out the Hawthorne structure for a sugar from the list given in class. Make sure to write out all atoms except for carbons within the ring. Make sure that groups off the carbons in the ring are in the correct orientation above or below the plane. Make sure that bonds are in the correct orientation. Include the full name of the sugar. You can draw out your curve within the text box or upload a drawing below.arrow_forwardHow many milliliters of 97.5(±0.5) wt% H2SO4 with a density of 1.84(±0.01) g/mL will you need to prepare 2.000 L of 0.110 M H2SO4? If the uncertainty in delivering H2SO4 is ±0.01 mL, calculate the absolute uncertainty in the molarity (0.110 M). Assume there is negligible uncertainty in the formula mass of H2SO4 and in the final volume (2.000 L) and assume random error.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- * How many milliliters of 97.5(±0.5) wt% H2SO4 with a density of 1.84(±0.01) g/mL will you need to prepare 2.000 L of 0.110 M H2SO4? * If the uncertainty in delivering H2SO4 is ±0.01 mL, calculate the absolute uncertainty in the molarity (0.110 M). Assume there is negligible uncertainty in the formula mass of NaOH and in the final volume (2.000 L) and assume random error.arrow_forwardYou are tasked with creating a calibration curve for the absorbance of cobalt solutions of various concentrations. You must prepare 5 standards with concentrations between 1.00 mg/L and 10.0 mg/L Co2+. You have a stock solution with a concentration of 40 mg/L Co2+ and all the standard lab glassware including transfer pipets and flasks. Explain how you would make your 5 standard solutions of various concentrations, including what glassware you would use to measure and prepare each solution.arrow_forwardPredict the product and write the mechanism. CH3-CH=CH-CH2-CH3 + NBS- hv CCl4arrow_forward
- How exactly is carbon disulfide used in industry? Specifically, where does it come in during rubber or textile production and what is the chemical processes?arrow_forwardA researcher has developed a new analytical method to determine the percent by mass iron in solids. To test the new method, the researcher purchases a standard reference material sample that is 2.85% iron by mass. Analysis of the iron standard with the new method returns values of 2.75%, 2.89%, 2.77%, 2.81%, and 2.87%. Does the new method produce a result that is significantly different from the standard value at the 95% confidence level?arrow_forwardCreate a drawing of an aceral with at least 2 isopropoxy groups, and a total of 11 carbon atomsarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)