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Basic Engineering Circuit Analysis
11th Edition
ISBN: 9781118539293
Author: J. David Irwin, R. Mark Nelms
Publisher: WILEY
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A Factory produces light bulbs from two different machines: Machine A and Machine B. The
probability that a randomly selected light bulbs is from Machine A is 60%, and the probability that a light
bulb is defective is 5%. Suppose that probability that a light bulb is defective given that it was made by
Machine A is 0.05. Similarly, the probability that a light bulb is defective given that it was made by
Machine B is 0.03. Are the events “the light bulb is from Machine A” and “the light bulb is defective”
independent?
3 (10pts). A Factory produces light bulbs from two different machines: Machine A and Machine B. The
probability that a randomly selected light bulbs is from Machine A is 60%, and the probability that a light
bulb is defective is 5%. Suppose that probability that a light bulb is defective given that it was made by
Machine A is 0.05. Similarly, the probability that a light bulb is defective given that it was made by
Machine B is 0.03. Are the events "the light bulb is from Machine A" and "the light bulb is defective"
independent?
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- A17)arrow_forwardUsing Carson's rule, determine the transmission bandwidth for commercial FM radio broadcasting, provided that the maximum value of frequency deviation is 75 kHz and the bandwidth of the audio signal is 15 kHzarrow_forward2. Laboratory Preliminary Discussion First-order High-pass RC Filter Analysis The first-order high-pass RC filter shown in figure 3 below represents all voltages and currents in the time domain. We will again convert the circuit to its s-domain equivalent as shown in figure 4 and apply Laplace transform techniques. ic(t) C vs(t) i₁(t) + + vc(t) R1 ww Vi(t) || 12(t) V2(t) R₂ Vout(t) VR2(t) = V2(t) Figure 3: A first-order high-pass RC filter represented in the time domain. Ic(s) C + Vs(s) I₁(s) + + Vc(s) R₁ www V₁(s) 12(s) V₂(s) R₂ Vout(S) = VR2(S) = V2(s) Figure 4: A first-order high-pass RC filter represented in the s-domain. Again, to generate the s-domain expression for the output voltage, You (S) = V2 (s), for the circuit shown in figure 4 above, we can apply voltage division in the s-domain as shown in equation 2 below. Equation 2 will be used in the prelab computations to find an expression for the output voltage, xc(t), in the time domain. equation (2) R₂ Vout(s) = V₂(s) = R₂+…arrow_forward
- Can you show me the steps to get the last part after the second equal sign.arrow_forwardPrelab Information 1. Laboratory Preliminary Discussion First-order Low-pass RC Filter Analysis The first-order low-pass RC filter shown in figure 1 below represents all voltages and currents in the time domain. It is of course possible to solve for all circuit voltages using time domain differential equation techniques, but it is more efficient to convert the circuit to its s-domain equivalent as shown in figure 2 and apply Laplace transform techniques. vs(t) i₁(t) + R₁ ww V₁(t) 12(t) Lic(t) Vout(t) = V2(t) R₂ Vc(t) C Vc(t) VR2(t) = V2(t) + Vs(s) Figure 1: A first-order low-pass RC filter represented in the time domain. I₁(s) R1 W + V₁(s) V₂(s) 12(s) Ic(s) + Vout(S) == Vc(s) Vc(s) Zc(s) = = VR2(S) V2(s) Figure 2: A first-order low-pass RC filter represented in the s-domain.arrow_forwardA.15 Consider a communication channel, transfer characteristic of which is defined by the nonlinear relation, y(t) = x(t) + x² (t), where x(t) is the input and y(t) is the output. Assuming the input is an FM signal, x(t) = cos (2лft+(t)), find y(t). Is it possible to retrieve x(t) from y(t)? If so, how?arrow_forward
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