Chapter 6, Problem 6A.3ST

Interpretation Introduction

Interpretation:

From the given data, the molar concentration of benzene has to be calculated.

Concept Introduction:

Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.

Molar mass: It is obtained by dividing the mass of substance with the amount of substance and the S.I. unit of molar mass is $\text{kg/mol}$. It is numerically equal to the molecular weight since molecular weight is sum of all individual atom weight present in molecule which is represented in $amu$.

  $\text{Molar}\text{mass}\left(\text{g/mol}\right)=\frac{\text{Given}\text{mass}\text{of}\text{substance}\left(\text{g}\right)}{\text{Moles}\text{of}\text{substance}\left(mol\right)}$

Beer-Lambert law: This theory explain that absorbance depends on the both the concentration of the sample and the length of the path through the sample, this relationship between absorbance, concentration, length of the light path and molar absorptivity, it is known as the Beer-Lambert law, it given some fallowing equation.

$\begin{array}{l}A=c\text{l}\epsilon \\ A=absorbanceofthesample\\ c=concentrationofthesample,inmoles/liter\\ \text{l}\text{=}Lengthofthelightpaththroughthesample,inconcentration\\ \epsilon =molarabsorptivity(M^{-1}c{m}^{-1})\end{array}$