The Bronsted acids and bases in both reactants and products of the given proton transfer equilibrium has to be identified. Concept Introduction: Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor. Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid. Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

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Answer 1

Question

Chapter 6, Problem 6A.2BST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products of the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

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(a 4 shows scanning electron microscope (SEM) images of extruded actions of packing bed for two capillary columns of different diameters, al 750 (bottom image) and b) 30-μm-i.d. Both columns are packed with the same stationary phase, spherical particles with 1-um diameter. A) When the columns were prepared, the figure shows that the column with the larger diameter has more packing irregularities. Explain this observation. B) Predict what affect this should have on band broadening and discuss your prediction using the van Deemter terms. C) Does this figure support your explanations in application question 33? Explain why or why not and make any changes in your answers in light of this figure. Figure 4 SEM images of sections of packed columns for a) 750 and b) 30-um-i.d. capillary columns.³

fcrip = ↓ bandwidth Il temp 32. What impact (increase, decrease, or no change) does each of the following conditions have on the individual components of the van Deemter equation and consequently, band broadening? Increase temperature Longer column Using a gas mobile phase instead of liquid Smaller particle stationary phase Multiple Paths Diffusion Mass Transfer

34. Figure 3 shows Van Deemter plots for a solute molecule using different column inner diameters (i.d.). A) Predict whether decreasing the column inner diameters increase or decrease bandwidth. B) Predict which van Deemter equation coefficient (A, B, or C) has the greatest effect on increasing or decreasing bandwidth as a function of i.d. and justify your answer. Figure 3 Van Deemter plots for hydroquinone using different column inner diameters (i.d. in μm). The data was obtained from liquid chromatography experiments using fused-silica capillary columns packed with 1.0-μm particles. 35 20 H(um) 큰 20 15 90 0+ 1500 100 75 550 01 02 594 05 μ(cm/sec) 30 15 10

Answer 2

Question

Chapter 6, Problem 6A.2BST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products of the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

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Answer 3

Question

Chapter 6, Problem 6A.2BST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products of the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Expert Solution & Answer

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Answer 4

Question

Chapter 6, Problem 6A.2BST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products of the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Expert Solution & Answer

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Answer 5

Chapter 6, Problem 6A.2BST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products of the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Answer 6

Chapter 6, Problem 6A.2BST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products of the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

Answer 7

Chapter 6, Problem 6A.2BST

(a)

Interpretation Introduction

Interpretation:

The Bronsted acids and bases in both reactants and products of the given proton transfer equilibrium has to be identified.

Concept Introduction:

Bronsted-Lowry acid is a proton donor as well Bronsted-Lowry base is a proton acceptor.

Conjugate acid of a base has one more proton than its base. Simply add a proton to the base to get its conjugate acid.

Conjugate base of an acid has one less proton than its acid. Simply remove a proton from the acid to get its conjugate base.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The Lewis acid and base in the given proton transfer equilibrium has to be identified.

Concept Introduction:

There is simple way to identify whether the given species is Lewis acid or Lewis base. A species which accepts electron pair is called Lewis acid and a species which donates electron pair is called Lewis base.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 6 - Prob. 6A.1AST Ch. 6 - Prob. 6A.1BST Ch. 6 - Prob. 6A.2AST Ch. 6 - Prob. 6A.2BST Ch. 6 - Prob. 6A.3AST Ch. 6 - Prob. 6A.3BST Ch. 6 - Prob. 6A.1E Ch. 6 - Prob. 6A.2E Ch. 6 - Prob. 6A.3E Ch. 6 - Prob. 6A.4E

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Chapter 6 Solutions