Chapter 6, Problem 6G.8E

(a)

Interpretation Introduction

Interpretation:

The $pHandpOH$ of a solution that is $0.23MN{a}_{2}HP{O}_4\left(aq\right)and0.18MN{a}_{3}P{O}_4\left(aq\right)$ has to be calculated.

Concept Introduction:

Henderson – Hasselbalch equation:

The $pH$ of a buffer can be easily calculated by using Henderson – Hasselbalch equation as given below.

  $pH=p{K}_a+\log \frac{{\left[base\right]}_{initial}}{{\left[acid\right]}_{initial}}$

(b)

Interpretation Introduction

Interpretation:

The $pHandpOH$ of a solution that is $0.45MN{a}_{2}HP{O}_4\left(aq\right)and0.62MN{a}_{3}P{O}_4\left(aq\right)$ has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The $pHandpOH$ of a solution that is $0.16MN{a}_{2}HP{O}_4\left(aq\right)and0.16MN{a}_{3}P{O}_4\left(aq\right)$ has to be calculated.

Concept Introduction:

Refer to part (a).