Introduction to Probability and Statistics
14th Edition
ISBN: 9781133103752
Author: Mendenhall, William
Publisher: Cengage Learning
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Chapter 6, Problem 6.91SE
(a)
To determine
To find: The proportion of observations that lie between 36.3 and 43.5.
(b)
To determine
To find: The measurements in which 95% of the observations would lie.
(c)
To determine
To find: The actual proportion for the part (a) and (b) and comment on the accuracy
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a) Determine the mean change in patient weight from before to after the
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In order to find probability, you can use this formula in Microsoft Excel:
The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest.
=NORM.DIST(x, Mean, Standard Dev., TRUE).
When the question mentions “greater than” you may have to subtract your answer from 1.
When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer.
1.
Compute the probability of a value between 44.0 and 55.0.
(The question requires finding probability value between 44 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 44, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the…
If a uniform distribution is defined over the interval from 6 to 10, then answer the followings:
What is the mean of this uniform distribution?
Show that the probability of any value between 6 and 10 is equal to 1.0
Find the probability of a value more than 7.
Find the probability of a value between 7 and 9.
The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be:
More than $27?
Less than or equal to $24?
The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches.
What is the mean amount of rainfall for the month?
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What is the probability of exactly 1.00 inch of rain?
What is the probability of more than 1.50 inches of rain for the month?
The best way to solve this problem is begin by creating a chart. Clearly mark the range, identifying the lower and upper…
Chapter 6 Solutions
Introduction to Probability and Statistics
Ch. 6.3 - Consider a standard normal random variable with =0...Ch. 6.3 - Find these probabilities associated with the...Ch. 6.3 - Calculate the area under the standard normal curve...Ch. 6.3 - Calculate the area under the standard normal curve...Ch. 6.3 - Find the following probabilities for the standard...Ch. 6.3 - Find these probabilities for the standard normal...Ch. 6.3 - a. Find a z0 such that P(zz0)=.025 . b. Find a z0...Ch. 6.3 - Prob. 6.8ECh. 6.3 - Prob. 6.9ECh. 6.3 - a. Find a z0 such that P(z0zz0)=.90 . b. Find a z0...
Ch. 6.3 - Find the following percentiles for the standard...Ch. 6.3 - A normal random variable x has mean =10 and...Ch. 6.3 - Prob. 6.13ECh. 6.3 - Prob. 6.14ECh. 6.3 - A normal random variable x has mean 35 and...Ch. 6.3 - Prob. 6.16ECh. 6.3 - A normal random variable x has an unknown mean and...Ch. 6.3 - Hamburger Meat The meat department at a local...Ch. 6.3 - Human Heights Human heights are one of many...Ch. 6.3 - Christmas Trees The diameters of Douglas firs...Ch. 6.3 - Cerebral Blood Flow Cerebral blood flow (CBF) in...Ch. 6.3 - Braking Distances For a car traveling 30 miles per...Ch. 6.3 - Elevator Capacities Suppose that you must...Ch. 6.3 - Sunflowers An experimenter publishing in the...Ch. 6.3 - Prob. 6.26ECh. 6.3 - Prob. 6.27ECh. 6.3 - Prob. 6.28ECh. 6.3 - Prob. 6.30ECh. 6.3 - How Many Words? A publisher has discovered that...Ch. 6.3 - Prob. 6.32ECh. 6.4 - Consider a binomial random variable x with n=25...Ch. 6.4 - Prob. 6.36ECh. 6.4 - Prob. 6.37ECh. 6.4 - Let x be a binomial random variable with n=15 and...Ch. 6.4 - Let x be a binomial random variable with n=100 and...Ch. 6.4 - Prob. 6.40ECh. 6.4 - Prob. 6.41ECh. 6.4 - Prob. 6.42ECh. 6.4 - Prob. 6.43ECh. 6.4 - Prob. 6.44ECh. 6.4 - Prob. 6.45ECh. 6.4 - Prob. 6.46ECh. 6.4 - No Shows Airlines and hotels often grant...Ch. 6.4 - Prob. 6.49ECh. 6.4 - Pepsi’s Market Share Two of the biggest soft drink...Ch. 6.4 - Prob. 6.52ECh. 6.4 - Prob. 6.53ECh. 6 - Prob. 6.54SECh. 6 - Prob. 6.55SECh. 6 - Prob. 6.56SECh. 6 - Prob. 6.57SECh. 6 - a. Find a z0 such that P(z0zz0)=.95 . b. Find a z0...Ch. 6 - Prob. 6.59SECh. 6 - Let x be a binomial random variable with n=36 and...Ch. 6 - Prob. 6.61SECh. 6 - Prob. 6.62SECh. 6 - Prob. 6.63SECh. 6 - Prob. 6.64SECh. 6 - Prob. 6.65SECh. 6 - Prob. 6.66SECh. 6 - Prob. 6.67SECh. 6 - Prob. 6.68SECh. 6 - Prob. 6.69SECh. 6 - Used Cars A used-car dealership has found that the...Ch. 6 - Washers The life span of a type of automatic...Ch. 6 - Prob. 6.74SECh. 6 - Prob. 6.75SECh. 6 - Prob. 6.77SECh. 6 - Prob. 6.78SECh. 6 - Prob. 6.79SECh. 6 - Prob. 6.80SECh. 6 - No Shows An airline finds that 5% of the persons...Ch. 6 - Prob. 6.82SECh. 6 - Plant Genetics In Exercise 5.75, a cross between...Ch. 6 - Prob. 6.84SECh. 6 - Prob. 6.86SECh. 6 - Prob. 6.87SECh. 6 - Introvert or Extrovert? A psychological...Ch. 6 - Normal Distribution? The chest measurements for...Ch. 6 - Prob. 6.91SECh. 6 - Prob. 6.92SECh. 6 - Prob. 6.93SECh. 6 - Prob. 6.94SECh. 6 - Prob. 6.95SECh. 6 - Prob. 6.96SECh. 6 - Prob. 6.97SE
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