Chapter 6, Problem 6.8P

Interpretation Introduction

Interpretation:

For given equilibrium reaction, the value of K has to be calculated.

Concept introduction:

Equilibrium constant (K): In the equilibrium reaction, the ratio of concentration of the reactant and concentration of the product.  If value of K is small than 1 the reaction should be move to the left and k is more than 1 the reaction should be move to right.

Relating ${\text{ΔG}}^{\text{0}}$to K:

$\begin{array}{l}{\text{ΔG}}^{\text{0}}\text{= -RTlnK}\\ \\ {\text{K = e}}^{\left({\text{-ΔG}}^{\text{0}}\text{/RT}\right)}\end{array}$

$\begin{array}{l}{\text{ΔG}}^{\text{0}}\text{-Change in free energy}\\ \\ \text{K-Equilibrium constant}\\ \\ \text{R-Gas constant (8}\text{.314472)}\\ \\ \text{T-Temperature}\end{array}$