Chapter 6, Problem 6.37P

(a)

Interpretation Introduction

Interpretation:

$\text{pH}$ of the water at $\text{25°C}$ has to be calculated.

Concept introduction:

The $\text{pH}$ of solution can be calculated as,

$\text{pH=-log}\left[{\text{H}}^{\text{+}}\right]$

The formula of ionic product of water is,

$K_w=\left[H^{+}\right]\left[O{H}^{-}\right]$

Where,

${\text{K}}_{\text{w}}\text{=1}\text{.0}\times {\text{10}}^{\text{-14}}$

(b)

Interpretation Introduction

Interpretation:

$\text{pH}$ of the water at $\text{100°C}$ has to be calculated.

Concept introduction:

The $\text{pH}$ of solution can be calculated as,

$\text{pH=-log}\left[{\text{H}}^{\text{+}}\right]$

The formula of ionic product of water is,

$K_w=\left[H^{+}\right]\left[O{H}^{-}\right]$

Where,

${\text{K}}_{\text{w}}\text{=1}\text{.0}\times {\text{10}}^{\text{-14}}$