Chapter 6, Problem 6.87AQAP

Interpretation Introduction

Interpretation:

Electron arrangement: Electron arrangement of atoms, or ions is down on the bas is of energy level. Electron first occupies the lower energy state, after that higher energy state. Energy of subshell is decided on the basis of $$ rule.

Where $n:$ shells number

$l:$ Subshells number.

If $\left(n+l\right)$ for two subshells are same, then the subshell. With high value of $n$ having higher energy level. Order of energy of subshell:

$1S<2S<2P<3S>3P<4S<3d<4P<5S<4d<5P<6S.$

Maximum no of electron in

$\begin{array}{l}S-\text{Subshell=2}\\ P-\text{Subshell=6}\\ d-\text{Subshell=10}\\ f-\text{Subshell=14}\text{.}\end{array}$

Concept introduction:

Fill the subshell with the electrons up to maximum capacity of subshell in increasing order of their energy.

No of electrons on action $=\text{atomic number}-\left(\text{No of positive charge}\right)$

No of electrons on action $=\text{atomic number + }\left(\text{No of }-ve\text{ charge}\right)$