Chapter 6, Problem 6.6P

(a)

Interpretation Introduction

Interpretation:

The molarity of $\text{Hg}{\left({\text{NO}}_{\text{3}}\right)}_{\text{2}}$ has to be calculated.

Concept-Introduction:

Acid–base titration: It consists of a neutralization reaction where a measured volume of a known concentrated an acid or a base is used for determining the concentration of an unknown solution of base or acid with known volume.  The known concentrated solution is called the titrant, while the unknown concentrated solution is called the analyte.

Molarity: The concentration for solutions is expressed in terms of molarity as follows,

  $\text{M = }\frac{\text{n}}{\text{V}}$

Where,

M is molarity; n is number of moles; and V is volume of solution in L.

(b)

Interpretation Introduction

Interpretation:

The concentration of ${\text{Cl}}^{\text{-}}$ in the urine has to be calculated.