66. m by n grid graphs . An m by n grid graph represents a rectangular street grid that is m . blocks by n blocks, as indicated in F i g . 6 - 5 1 . _ F i g u r e 6 - 5 1 a. If m and n are both odd, then the m by n grid graph has a Hamilton circuit. Describe the circuit by drawing it on a generic graph. b. If either m or n is even and the other one is odd, then the m by n grid graph has Hamilton circuit. Describe the circuit by drawing it on a generic graph. c. . If m and n are both even, then the m by n grid graph does not have a Hamilton circuit. Explain why a Hamilton circuit is impossible.
66. m by n grid graphs . An m by n grid graph represents a rectangular street grid that is m . blocks by n blocks, as indicated in F i g . 6 - 5 1 . _ F i g u r e 6 - 5 1 a. If m and n are both odd, then the m by n grid graph has a Hamilton circuit. Describe the circuit by drawing it on a generic graph. b. If either m or n is even and the other one is odd, then the m by n grid graph has Hamilton circuit. Describe the circuit by drawing it on a generic graph. c. . If m and n are both even, then the m by n grid graph does not have a Hamilton circuit. Explain why a Hamilton circuit is impossible.
Solution Summary: The author explains that a Hamilton circuit contains all the vertices of the graph exactly once except first and last vertex.
66. m by n grid graphs. An m by n grid graph represents a rectangular street grid that is m. blocks by n blocks, as indicated in
F
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6
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5
1
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F
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g
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6
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5
1
a. If m and n are both odd, then the m by n grid graph has a Hamilton circuit. Describe the circuit by drawing it on a generic graph.
b. If either m or n is even and the other one is odd, then the m by n grid graph has Hamilton circuit. Describe the circuit by drawing it on a generic graph.
c. . If m and n are both even, then the m by n grid graph does not have a Hamilton circuit. Explain why a Hamilton circuit is impossible.
By considering appropriate series expansions,
ex · ex²/2 . ¸²³/³ . . ..
=
= 1 + x + x² +……
when |x| < 1.
By expanding each individual exponential term on the left-hand side
and multiplying out, show that the coefficient of x 19 has the form
1/19!+1/19+r/s,
where 19 does not divide s.
Let
1
1
r
1+
+ +
2 3
+
=
823
823s
Without calculating the left-hand side, prove that r = s (mod 823³).
For each real-valued nonprincipal character X mod 16, verify that
L(1,x) 0.
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