A luggage handler pulls a 20.0-kg suitcase up a ramp inclined at 32.0° above the horizontal by a force F of magnitude 160 N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is = 0.300. If the suitcase travels 3.80 m along the ramp, calculate (a) the work done on the suitcase by F; (b) the work done on the suitcase by the gravitational force; (c) the work done on the suitcase by the normal force; (d) the work done on the suitcase by the friction force; (e) the total work done on the suitcase, (f) If the speed of the suit-case is zero at the bottom of the ramp, what is its speed after it has traveled 3.80 m along the ramp?
A luggage handler pulls a 20.0-kg suitcase up a ramp inclined at 32.0° above the horizontal by a force F of magnitude 160 N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is = 0.300. If the suitcase travels 3.80 m along the ramp, calculate (a) the work done on the suitcase by F; (b) the work done on the suitcase by the gravitational force; (c) the work done on the suitcase by the normal force; (d) the work done on the suitcase by the friction force; (e) the total work done on the suitcase, (f) If the speed of the suit-case is zero at the bottom of the ramp, what is its speed after it has traveled 3.80 m along the ramp?
A luggage handler pulls a 20.0-kg suitcase up a ramp inclined at 32.0° above the horizontal by a force F of magnitude 160 N that acts parallel to the ramp. The coefficient of kinetic friction between the ramp and the incline is = 0.300. If the suitcase travels 3.80 m along the ramp, calculate (a) the work done on the suitcase by F; (b) the work done on the suitcase by the gravitational force; (c) the work done on the suitcase by the normal force; (d) the work done on the suitcase by the friction force; (e) the total work done on the suitcase, (f) If the speed of the suit-case is zero at the bottom of the ramp, what is its speed after it has traveled 3.80 m along the ramp?
You're on an interplanetary mission, in an orbit around the Sun. Suppose you make a maneuver that brings your perihelion in closer to the Sun but leaves your aphelion unchanged. Then you must have
Question 2 options:
sped up at perihelion
sped up at aphelion
slowed down at perihelion
slowed down at aphelion
The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE DO NOT USE LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
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