
(a)
The extension of the spring for a mass of
(a)

Answer to Problem 65P
The extension of the spring for a mass of
Explanation of Solution
Write the expression for
Here,
Write the expression for velocity in terms of time period.
Here,
Write the expression for force from hooks law.
Here,
Use equation (II) and (III) in equation (I) and rearrange.
Write the expression for radius of the pluck’s motion.
Use equation (V) in equation (IV), to find
Conclusion:
Therefore, the extension of the spring for a mass of
(b)
The extension of the spring for the mass
(b)

Answer to Problem 65P
The extension of the spring for the mass
Explanation of Solution
Substitute
Conclusion:
Substitute
Therefore, the extension of the spring for the mass
(c)
The extension of the spring for the mass
(c)

Answer to Problem 65P
The extension of the spring for the mass
Explanation of Solution
From equation (VII).
Conclusion:
Substitute
Therefore, the extension of the spring for the mass
(d)
The extension of the spring for the mass
(d)

Answer to Problem 65P
The extension of the spring for the mass
Explanation of Solution
From equation (VII).
Conclusion:
Substitute
Therefore, the extension of the spring for the mass
(e)
The extension of the spring for the mass
(e)

Answer to Problem 65P
For the mass
Explanation of Solution
From equation (VII) the spring extension is given by
Conclusion:
Substitute
Therefore, For the mass
(f)
To explain the pattern of variation of
(f)

Answer to Problem 65P
The extension of the spring is directly proportional to the mass
Explanation of Solution
The extension of the spring is directly proportional to the mass
Conclusion:
Therefore, the extension of the spring is directly proportional to the mass
Want to see more full solutions like this?
Chapter 6 Solutions
Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)
- RT = 4.7E-30 18V IT = 2.3E-3A+ 12 38Ω ли 56Ω ли r5 27Ω ли r3 28Ω r4 > 75Ω r6 600 0.343V 75.8A Now figure out how much current in going through the r4 resistor. |4 = unit And then use that current to find the voltage drop across the r resistor. V4 = unitarrow_forward7 Find the volume inside the cone z² = x²+y², above the (x, y) plane, and between the spheres x²+y²+z² = 1 and x² + y²+z² = 4. Hint: use spherical polar coordinates.arrow_forwardганм Two long, straight wires are oriented perpendicular to the page, as shown in the figure(Figure 1). The current in one wire is I₁ = 3.0 A, pointing into the page, and the current in the other wire is 12 4.0 A, pointing out of the page. = Find the magnitude and direction of the net magnetic field at point P. Express your answer using two significant figures. VO ΜΕ ΑΣΦ ? Figure P 5.0 cm 5.0 cm ₁ = 3.0 A 12 = 4.0 A B: μΤ You have already submitted this answer. Enter a new answer. No credit lost. Try again. Submit Previous Answers Request Answer 1 of 1 Part B X Express your answer using two significant figures. ΜΕ ΑΣΦ 0 = 0 ? below the dashed line to the right P You have already submitted this answer. Enter a new answer. No credit lost. Try again.arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning





