Basic Chemistry (5th Edition)
5th Edition
ISBN: 9780134138046
Author: Karen C. Timberlake
Publisher: PEARSON
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Chapter 6, Problem 6.57FU
(a)
Interpretation Introduction
Interpretation:
The chemical formula of the magnesium sulfate is to be stated.
Concept Introduction:
A chemical formula of a given compound is used to describe the number of atoms present in it. Since a compound is made of two or more than two different elements in definite proportion, a chemical formula can best describe the number of elements it contains with their atomic symbols.
(a)
Expert Solution
Answer to Problem 6.57FU
The chemical formula of magnesium sulfate is MgSO4.
Explanation of Solution
Magnesium is a second group element belonging to the alkaline earth metal family. To obtain stable noble gas configurationit loses two electrons and forms Mg2+.
Sulfate ion is a polyatomic ion which is composed of one sulfur and four oxygen atoms.It carries a charge of -2.
Hence, in magnesium sulfate, magnesium transfers two of its electrons to sulfate ion which results in the formation of an ionic compound known as MgSO4.
(b)
Interpretation Introduction
Interpretation:
The chemical formula of tin (II) fluoride is to be stated.
Concept Introduction:
A chemical formula of a given compound is used to describe the number of atoms present in it. Since a compound is made of two or more than two different elements in definite proportion, a chemical formula can best describe the number of elements it contains with their atomic symbols.
(b)
Expert Solution
Answer to Problem 6.57FU
The chemical formula of tin (II) fluoride is SnF2.
Explanation of Solution
Tin or ‘Sn’ is a fourteen group element belonging to the Carbon family. Hence ‘Sn’looses two of its electrons to form Sn2+. Fluorine is a seventeen group element belonging to the halogens family and is non-metallic in nature therefore it gains one electron to form F-.When the chemical formula of an ionic compound is written, the superscript which denotes the charge on the cation becomes the subscript of the anion and vice-versa.
The chemical formula of the resulting compound is SnF2.
(c)
Interpretation Introduction
Interpretation:
The chemical formula of aluminum hydroxide is to be stated.
Concept Introduction:
A chemical formula of a given compound is used to describe the number of atoms present in it. Since a compound is made of two or more than two different elements in definite proportion, a chemical formula can best describe the number of elements it contain with their atomic symbols.
(c)
Expert Solution
Answer to Problem 6.57FU
The chemical formula of aluminum hydroxide is Al (OH)3.
Explanation of Solution
Aluminum or ‘Al’is a thirteen group element belonging to the Boron family. After losing three electrons from its valence shell Al forms trivalent Al3+ cation. Hydroxide ion is a diatomic ion which consists of oxygen and hydrogen atom bonded covalently and it carries a negative charge. When Al loses three electrons and results in Al3+,three OH gains one electron each and results in OH- to form an ionic compound named as Al (OH)3 or commonly known as aluminum hydroxide. When the chemical formula of an ionic compound is written, the superscript which denotes the charge on the cation becomes the subscript of the anion and vice-versa.
Thus, chemical formula of the resulting compound is Al (OH)3.
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Students have asked these similar questions
Predict the organic products that form in the reaction below:
H.
H+
+
OH
H+
Y
Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the
products.
In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the
structures in any arrangement that you like, so long as they aren't touching.
Explanation
Check
Click and drag to start drawing a
structure.
G
X
C
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+
111
Carbonyl Chem
Choosing reagants for a Wittig reaction
What would be the best choices for the missing reagents 1 and 3 in this synthesis?
1. PPh3
3
1
2
2. n-BuLi
• Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like.
Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is.
• Note: if one of your reagents needs to contain a halogen, use bromine.
Explanation
Check
Click and drag to start drawing a structure.
×
©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use
A student proposes the transformation below in one step of an organic synthesis. There may be one or more reactants missing from the left-hand side, but there
are no products missing from the right-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from
the arrow.
• Is the student's transformation possible? If not, check the box under the drawing area.
. If the student's transformation is possible, then complete the reaction by adding any missing reactants to the left-hand side, and adding required catalysts,
inorganic reagents, or other important reaction conditions above and below the arrow.
• You do not need to balance the reaction, but be sure every important organic reactant or product is shown.
+
T
X
O
O
лет-ле
HO
OH
HO
OH
This transformation can't be done in one step.
Chapter 6 Solutions
Basic Chemistry (5th Edition)
Ch. 6.1 - State the number of electrons that must be lost by...Ch. 6.1 - Prob. 6.2QAPCh. 6.1 - State the number of electrons lost or gained when...Ch. 6.1 - State the number of electrons lost or gained when...Ch. 6.1 - Prob. 6.5QAPCh. 6.1 - Prob. 6.6QAPCh. 6.1 - Prob. 6.7QAPCh. 6.1 - Prob. 6.8QAPCh. 6.1 - Prob. 6.9QAPCh. 6.1 - Prob. 6.10QAP
Ch. 6.1 - Prob. 6.11QAPCh. 6.1 - Prob. 6.12QAPCh. 6.1 - Prob. 6.13QAPCh. 6.1 - Prob. 6.14QAPCh. 6.2 - Which of the following pairs of elements are...Ch. 6.2 - Which of the following pairs of elements are...Ch. 6.2 - 6.13 Write the correct ionic formula for the...Ch. 6.2 - Prob. 6.18QAPCh. 6.2 - Prob. 6.19QAPCh. 6.2 - Prob. 6.20QAPCh. 6.3 - Prob. 6.21QAPCh. 6.3 - Write the name for each of the following ionic...Ch. 6.3 - Prob. 6.23QAPCh. 6.3 - Prob. 6.24QAPCh. 6.3 - Prob. 6.25QAPCh. 6.3 - Prob. 6.26QAPCh. 6.3 - Prob. 6.27QAPCh. 6.3 - Prob. 6.28QAPCh. 6.3 - Prob. 6.29QAPCh. 6.3 - Prob. 6.30QAPCh. 6.3 - Prob. 6.31QAPCh. 6.3 - Write the formula for each of the following ionic...Ch. 6.3 - Prob. 6.33QAPCh. 6.3 - Prob. 6.34QAPCh. 6.4 - Write the formula including the charge for each of...Ch. 6.4 - Prob. 6.36QAPCh. 6.4 - Prob. 6.37QAPCh. 6.4 - Prob. 6.38QAPCh. 6.4 - 6.35 Complete the following table with the formula...Ch. 6.4 - Complete the following table with the formula and...Ch. 6.4 - Prob. 6.41QAPCh. 6.4 - Prob. 6.42QAPCh. 6.4 - Prob. 6.43QAPCh. 6.4 - 6. 40 Write the formula for the polyatomic ion and...Ch. 6.4 - 6.41 Name each of the following ionic compounds:...Ch. 6.4 - Prob. 6.46QAPCh. 6.5 - Name each of the following molecular compounds: a....Ch. 6.5 - Prob. 6.48QAPCh. 6.5 - Prob. 6.49QAPCh. 6.5 - Prob. 6.50QAPCh. 6.5 - Write the formula for each of the following...Ch. 6.5 - Prob. 6.52QAPCh. 6.5 - Write the formula for each of the following...Ch. 6.5 - Write the formula for each of the following...Ch. 6.5 - Prob. 6.55QAPCh. 6.5 - Prob. 6.56QAPCh. 6 - Prob. 6.57FUCh. 6 - Prob. 6.58FUCh. 6 - Prob. 6.59FUCh. 6 - Prob. 6.60FUCh. 6 - Prob. 6.61UTCCh. 6 - a. How does the octet rule explain the formation...Ch. 6 - Prob. 6.63UTCCh. 6 - Prob. 6.64UTCCh. 6 - Prob. 6.65UTCCh. 6 - Prob. 6.66UTCCh. 6 - Prob. 6.67UTCCh. 6 - Prob. 6.68UTCCh. 6 - Prob. 6.69AQAPCh. 6 - Prob. 6.70AQAPCh. 6 - Prob. 6.71AQAPCh. 6 - Prob. 6.72AQAPCh. 6 - Prob. 6.73AQAPCh. 6 - Prob. 6.74AQAPCh. 6 - Prob. 6.75AQAPCh. 6 - Prob. 6.76AQAPCh. 6 - Prob. 6.77AQAPCh. 6 - Prob. 6.78AQAPCh. 6 - Prob. 6.79AQAPCh. 6 - Prob. 6.80AQAPCh. 6 - Prob. 6.81AQAPCh. 6 - Prob. 6.82AQAPCh. 6 - Prob. 6.83AQAPCh. 6 - Prob. 6.84AQAPCh. 6 - Prob. 6.85CQCh. 6 - Prob. 6.86CQCh. 6 - Prob. 6.87CQCh. 6 - Prob. 6.88CQCh. 6 - Classify each of the following as ionic or...Ch. 6 - Prob. 6.90CQ
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