Chapter 6, Problem 6.53P

(a)

Interpretation Introduction

Interpretation:

Moles of $\text{Ca}{\left(\text{OH}\right)}_{\text{2}}$ in $\text{1}\text{.00L}$ of water has to be calculated.

Concept introduction:

Mole is standard unit for measuring amount of particle or atom or molecule present in the solution.

(b)

Interpretation Introduction

Interpretation:

How the solubility found in part (a) be affected by reaction of ${\text{K}}_{\text{1}}$ in given the following has to be explained.

$\begin{array}{l}\text{M}{\left(\text{OH}\right)}_{\text{2}\left(\text{s}\right)}\stackrel{}{\rightleftharpoons }{\text{M}}^{\text{2+}}{\text{+2OH}}^{\text{-}}\\ \\ {\text{K}}_{\text{sp}}\text{=}\left[{\text{M}}^{\text{2+}}\right]{\left[{\text{OH}}^{\text{-}}\right]}^{\text{2}}\\ \\ {\text{M}}^{\text{2+}}{\text{+OH}}^{\text{-}}\stackrel{}{\rightleftharpoons }{\text{MOH}}^{\text{+}}\\ \\ {\text{K}}_{\text{1}}\text{=}\left[{\text{MOH}}^{\text{+}}\right]\text{/}\left[{\text{M}}^{\text{2+}}\right]\left[{\text{OH}}^{\text{-}}\right]\\ \end{array}$