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Concept explainers
Interpretation:
The explanation why compounds containing elements in the third period of the periodic table and beyond doesn’t obey the octet rule has to be given.
Concept Introduction:
Octet Rule:
The octet rule states that the noble gas electron configuration is attained by the element, when the element either loses or gains or shares its atoms. The formulas for the compounds that contain specific elements can be predicted with the help of Octet rule. The octet rule holds good for those compounds that are made of elements present in second period and hence the important study on organic compounds that mainly consists of Carbon, Nitrogen and Oxygen atoms can be done with the help of Octet rule. The loss gain or sharing electrons of particular atom is dependent on properties of atoms that are determined by the number of subatomic particles inside in the atom.
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Chapter 6 Solutions
Chemistry: Atoms First
- CH3 CH H3C CH3 H OH H3C- -OCH2CH3 H3C H -OCH3 For each of the above compounds, do the following: 1. List the wave numbers of all the IR bands in the 1350-4000 cm-1 region. For each one, state what bond or group it represents. 2. Label equivalent sets of protons with lower-case letters. Then, for each 1H NMR signal, give the 8 value, the type of splitting (singlet, doublet etc.), and the number protons it represents. of letter δ value splitting # of protons 3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the 5 value and # of carbons it represents. letter δ value # of carbonsarrow_forwardDraw the correct ionic form(s) of arginine at the pKa and PI in your titration curve. Use your titration curve to help you determine which form(s) to draw out.arrow_forwardPlease correct answer and don't use hand ratingarrow_forward
- Nonearrow_forwardNonearrow_forwardCarbohydrates- Draw out the Hawthorne structure for a sugar from the list given in class. Make sure to write out all atoms except for carbons within the ring. Make sure that groups off the carbons in the ring are in the correct orientation above or below the plane. Make sure that bonds are in the correct orientation. Include the full name of the sugar. You can draw out your curve within the text box or upload a drawing below.arrow_forward
- How many milliliters of 97.5(±0.5) wt% H2SO4 with a density of 1.84(±0.01) g/mL will you need to prepare 2.000 L of 0.110 M H2SO4? If the uncertainty in delivering H2SO4 is ±0.01 mL, calculate the absolute uncertainty in the molarity (0.110 M). Assume there is negligible uncertainty in the formula mass of H2SO4 and in the final volume (2.000 L) and assume random error.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardWhat should be use to complete the reaction? CN CNarrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward* How many milliliters of 97.5(±0.5) wt% H2SO4 with a density of 1.84(±0.01) g/mL will you need to prepare 2.000 L of 0.110 M H2SO4? * If the uncertainty in delivering H2SO4 is ±0.01 mL, calculate the absolute uncertainty in the molarity (0.110 M). Assume there is negligible uncertainty in the formula mass of NaOH and in the final volume (2.000 L) and assume random error.arrow_forward
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