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A seaplane of total mass m lands on a lake with initial speed
(a) Carry nut the integration to determine the speed of the seaplane as a function of time. (b) Sketch a graph of the speed as a function of time. (c) Does the seaplane come to a complete stop after a finite interval of time? (d) Does the seaplane travel a finite distance in stopping?
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EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- You drop an object of mass m from a tall building. Suppose the only forces affecting its motion are gravity, and air resistance proportional to the object's speed with positive constant of proportionality k. Let g denote gravitational acceleration (a positive constant). Express the total force in terms of m, g, and the object's velocity v, where upward displacement is considered positive. F = mg - kv Newton's second law tells us that force is equal to mass x acceleration, F = ma. Relating acceleration to velocity, rewrite the equation for total force above as a first order differential equation for v as a function of t. Denote v' as dv dt v(t) m(- dr) this is not an equation. Solve this differential equation for v(t) with the initial condition v(0) = V0. = mg (1-e ==) m k Find the terminal Terminal velocity = mg k X velocity. X syntax error: X Xarrow_forwardA pendulum has a length l (the rope is massless). The mass of the object suspended from the pendulum is m. With rope horizontal θ = 90o When it makes an angle of degrees, we first leave the object at no speed. Any friction can be neglected. Gravitational acceleration g. Give your answers in terms of l, m and g. When = 0o, what is the tension in the rope?arrow_forwardThe highest spot on Earth is Mt. Everest, which is 8850 m above sea level. If the radius of the Earth (to sea level) is 6370 km, how much does the magnitude of g change between sea level and the top of Mt. Everest? (G = 6.67 × 10-11 N m2/kg2, and the mass of the Earth is 5.98 × 1024 kg.)arrow_forward
- An electron is a subatomic particle (m = 9.11 x 1031 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +5.72 x 105 m/s to a final velocity of 2.64 x 106 m/s while traveling a distance of 0.0783 m. The electron's acceleration is due to two electric forces parallel to the x axis: F1 = 9.44 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F F FF Voarrow_forwardAn electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +7.67 x 105 m/s to a final velocity of 2.57 x 106 m/s while traveling a distance of 0.0857 m. The electron's acceleration is due to two electric forces parallel to the x axis: = 7.62 x 10-17 N, and , which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force .arrow_forwardAn electron is a subatomic particle (m= 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +7.31 x 105 m/s to a final velocity of 1.98 x 106 m/s while traveling a distance of 0.0545 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.52 x 10-¹7 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F₁ F₁ F₂ F₁ (a) Number i (b) Number i VO X Units Unitsarrow_forward
- Inverted Pendulum: A pendulum of certain mass 'm' is attached to a rod of length 'I' and is constrained to move on xy-plane (see Figure above). After applying appropriate physical laws and relevant approximations, it is found that the angle e follows the following ordinary differential equation(ODE): انتقل إلى الإعدادت لتنشيد Here g = 9.81 m/s, the acceleration due to gravity. Solve the above ODE using ode45 from t = 0 to 2.5 sec witha step size of 0.1 sec. Plot 0(t) and e(t) in the same plot from t = 0 to 2.5sec Use I= 0.5 m and initial conditions e(0) 0.0 and é(t) = 0.25 (HINT: You need to decompose the above second order ODE into two first order ODES)arrow_forwardAn electron is a subatomic particle (m accelerates from an initial velocity of +7.54 x 105 m/s to a final velocity of 2.22 x 106 m/s while traveling a distance of 0.0692 m. = 9.11 x 1031 kg) that is subject to electric forces. An electron moving in the +x direction The electron's acceleration is due to two electric forces parallel to the axis: F1 9.04 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2 F, F2 F, on with available attempts. (a) Number Units (b) Number Unitsarrow_forwardExpress the force F as a vector in terms of the unit vectors i, j, and k. Determine the angles 0x, 0y, and 0, which F makes with the positive x-, y, and z-axes. 2, mm | В (-25, 50, 40) F = 750 N y, mm А (15, -20, -25) X, mmarrow_forward
- A player hits a ball with a speed of 39 m/s at an angle of Ɵ= 54 at a place where gravity is equal to 9.8 m/s 2 a. Find the x using this equation: x=Vo cos Ɵ t b. Find the y using : y=Vo sin Ɵ t – ½ gt2 c. Find the velocity of x and y d. Find the velocity along x axis using Vx= Vo cos Ɵ Vy= Vo sin Ɵ gtarrow_forwardAn electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +6.88 x 105 m/s to a final velocity of 2.30 x 106 m/s while traveling a distance of 0.0685 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.84 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. F₂ F₁ VO (a) Number i ! Units N (b) Number Units N eTextbook and Media -> C Σ > F2 F₁ וום 1 0> Assistance Usedarrow_forwardAn electron is a subatomic particle (m = 9.11 x 10-31 kg) that is subject to electric forces. An electron moving in the +x direction accelerates from an initial velocity of +6.88 x 105 m/s to a final velocity of 2.30 x 106 m/s while traveling a distance of 0.0685 m. The electron's acceleration is due to two electric forces parallel to the x axis: F₁ = 7.84 x 10-17 N, and F2, which points in the -x direction. Find the magnitudes of (a) the net force acting on the electron and (b) the electric force F2. (a) Number (b) Number i eTextbook and Media Hint F₂ F₁ ! Units N Units N M ון! > F₁arrow_forward
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