Chapter 6, Problem 6.41QP

Interpretation Introduction

Interpretation:

The enthalpy of formation of ${\text{P}}_{\text{4}}{\text{S}}_{\text{3}}$ value has to be given by using the ${\text{ΔH}}_{\text{rxn}}$ value.

Concept introduction:

Enthalpy change of reaction:

The enthalpy change of a reaction is calculated by

$\begin{array}{l}{\text{ΔH}}^{\text{o}}{}_{\text{rxn}}\text{=}{\displaystyle \sum {\text{nΔH}}_{\text{f}}^{\text{o}}\left(\text{products}\right)}\text{-}{\displaystyle \sum {\text{mΔH}}_{\text{f}}^{\text{o}}\left(\text{reactants}\right)}\\ \text{where,}\\ {\text{ΔH}}^{\text{o}}{}_{\text{rxn}}\text{-}\text{Standard}\text{enthalpy}\text{change}\text{of}\text{reaction}\\ {\text{ΔH}}_{\text{f}}^{\text{o}}\text{-}\text{Standard}\text{enthalpy}\text{change}\text{of}\text{formation}\end{array}$