EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
9th Edition
ISBN: 8220103611718
Author: SOBHAN
Publisher: CENGAGE L
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Chapter 6, Problem 6.3P
To determine

Find the zero–air–void unit weights for a soil at different moisture contents.

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Question 6: Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the volume of a particular sample of Cl₂ gas is 8.70 L at 895 torr and 24°C. (a) How many grams of Cl₂ are in the sample? ⚫ Atomic mass of CI = 35.453 g/mol • Molar mass of Cl₂ = 2 x 35.453 = 70.906 g/mol Solution: Use the Ideal Gas Law: Step 1: Convert Given Values • Pressure: P = 895 torr → atm PV= = nRT 1 P = 895 × = 1.1789 atm 760 • Temperature: Convert to Kelvin: T24273.15 = 297.15 K • Gas constant: R = 0.0821 L atm/mol. K Volume: V = 8.70 L Step 2: Solve for n . PV n = RT n = (1.1789)(8.70) (0.0821)(297.15) 10.25 n = = 0.420 mol 24.405 Step 3: Calculate Mass of Cl₂ Final Answer: 29.78 g of Cl₂. mass nx M mass= (0.420)(70.906) mass= 29.78 g
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1. Design a PVC sanitary sewer collection system for the Village of Waffle (Figure P-17-24 B, shown below) by preparing a sewer design table similar to that shown in Example 19-2 and a profile drawing similar to Figure 19-13b B. You only need to show the calculations for the pipes running along Bacon Road and Eggs Road, starting at point F and ending at Point B in the figure below. Your design should comply with the requirements specified in Chapter 30 of the 10 States Standards for Wastewater. Use the following assumptions: 0 о о Average daily flow rate is the same as average daily water demand, 9.2 m³/hr Peaking factor for peak dry weather flow is 6.2 Peak wet weather flow is equal to the peak dry weather flow plus an assumption for infiltration and inflow at 40 L/d-mm-km of pipe DODO on Ro 450 m 28 m D. 150 m Apartments D 400 m D 200 m B 250 m 0 Dogs Road ROOD625 m -120 m Syrup River 120 m 100-Year flood Point Elevation Tank 137.0 m A 130.0 m B 122.0 m C 122.3 m D 122.6 m A D 300 m…
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