Organic Chemistry Study Guide and Solutions
Organic Chemistry Study Guide and Solutions
6th Edition
ISBN: 9781936221868
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 6, Problem 6.38AP
Interpretation Introduction

(a)

Interpretation:

The sawhorse projections of all three staggered and all three eclipsed conformations of ephedrine are to be drawn by the rotation about the C1C2 bond.

Concept introduction:

The sawhorse representation is used to show the above carbon atom on right side in a molecule. The staggered from forms when all-atom is away from each other. The eclipsed form forms when all two atoms come in front of each other. The potential energy of the eclipsed form is higher than that of staggered form.

Interpretation Introduction

(b)

Interpretation:

The chirality of each conformation of ephedrine is to be examined. The way in which chiralities of the conformation of ephedrine are related to the overall chirality of ephedrine is to be stated.

Concept introduction:

A carbon atom that has four nonequivalent atoms or groups attached to it is known as the chiral carbon atom. Chiral carbon centers are also called asymmetric or stereogenic centers. A carbon atom that does not have four nonequivalent atoms or groups attached to it is known as an achiral carbon atom.

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If molecules A and B are isomers of each other, then what kinds of isomers could they be (i.e., enantiomers, diastereomers, or constitutional isomers) under each of the following conditions?(a) Both molecules have the same IHD.(b) Molecule A has a ring but molecule B does not.(c) Molecules A and B contain different functional groups.(d) Molecules A and B share exactly the same functional groups.(e) Molecule A has a plane of symmetry but molecule B does not.
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