Chemistry for Today: General  Organic  and Biochemistry
Chemistry for Today: General Organic and Biochemistry
9th Edition
ISBN: 9781337514576
Author: Seager
Publisher: Cengage
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Chapter 6, Problem 6.24E
Interpretation Introduction

Interpretation:

The unknown quantity for the given gas samples are to be calculated.

Concept introduction:

The ideal gas equation is used to represent the relation between the volume, pressure, temperature and number of moles of an ideal gas. The ideal gas equation is given as,

PV=nRT

Where,

V represents the volume occupied by the ideal gas.

P represents the pressure of the ideal gas.

n represents the number of moles of the ideal gas.

T represents the temperature of the ideal gas.

R represents the ideal gas constant with value 0.0821LatmK1mol1.

Expert Solution & Answer
Check Mark

Answer to Problem 6.24E

The final pressure of given sample A is 1.50atm.

The final volume of given sample B is 4.49L.

The final temperature of given sample C is 220.55K.

Explanation of Solution

The combined gas law is,

PiViTi=PfVfTf

Where,

Pi and Pf is the initial and final pressure.

Vi and Vf is the initial and final volume.

Ti and Tf is the initial and final temperature.

For sample A,

The initial pressure is 1.50atm.

The initial volume is 2.00L.

The initial temperature is 300K.

The final volume is 3.00L.

The final temperature is 450K.

To calculate the final pressure the formula used is,

Pf=PiViTfTiVf

Substitute the values of initial and final volume, initial and final temperature and initial pressure to calculate the value of final pressure.

Pf=1.50atm×2.00L×450K300K×3.00L=1.50atm

Thus, the final pressure of given sample A is 1.50atm.

For sample B,

The initial pressure is 2.35atm.

The initial volume is 1.97L.

The initial temperature is 293K.

The final pressure is 1.09atm.

The final temperature is 310K.

To calculate the final volume the formula used is,

Vf=PiViTfTiPf

Substitute the values of initial volume, initial and final temperature and initial and final pressure to calculate the value of final volume.

Vf=2.35atm×1.97L×310K293K×1.09atm=4.49L

Thus, the final volume of given sample B is 4.49L.

For sample C,

The initial pressure is 9.86atm.

The initial volume is 11.7L.

The initial temperature is 500K.

The final pressure is 5.14atm.

The final volume is 9.90L.

To calculate the final temperature the formula used is,

Tf=PfVfTiPiVi

Substitute the values of initial and final volume, initial temperature and initial and final pressure to calculate the value of final temperature.

Tf=5.14atm×9.90L×500K9.86atm×11.7L=220.55K

Thus, the final temperature of given sample C is 220.55K.

Conclusion

The final pressure of given sample A is 1.50atm.

The final volume of given sample B is 4.49L.

The final temperature of given sample C is 220.55K.

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Chapter 6 Solutions

Chemistry for Today: General Organic and Biochemistry

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