EBK USING MIS
10th Edition
ISBN: 9780134658919
Author: KROENKE
Publisher: YUZU
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Chapter 6, Problem 6.22MML
Explanation of Solution
Cloud:
The term cloud can be defined as the process that let the computer resources to be accessed anytime anywhere over the internet. The cloud can be represented as the elastic leasing of the various computer resources that are known as the pooled resources that can be accessed over the internet.
Merits that the cloud brings:
- Organization can readily gain elastic resources at low cost.
- Using this trend, from individual get benefits on iCloud or Google Drive, to small companies using Office 365, to Organizations like Falcon Security using PaaS service, and so on.
- Hence, the size of the cloud gets increased.
Software-as-a Service (SaaS):
- Software-as-a-Service (SaaS) is the mostly used service in cloud computing.
- In SaaS, the software is deployed from a cloud provider; internet is used to deliver the service and the subscribers access the service through the browser.
- The subscription of SaaS has some primary reasons:
- Risk is limited.
- Deployment is performed rapidly.
- Fewer upfront cost
- Increased reliability as seen in reduced down time
- Backup procedures are standardized.
- Total cost of ownership is lower because the purchase of hardware, software, license agreements, personal requirement for system run and administer are reduced through the SaaS cloud service...
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D. S. Malik, Data Structures Using C++, 2nd Edition, 2010
Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
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Chapter 6 Solutions
EBK USING MIS
Ch. 6.3 - Prob. 1EGDQCh. 6.3 - Prob. 2EGDQCh. 6.3 - Prob. 3EGDQCh. 6.3 - Prob. 4EGDQCh. 6.3 - Prob. 5EGDQCh. 6.3 - Prob. 6EGDQCh. 6.3 - Prob. 7EGDQCh. 6.3 - Prob. 8EGDQCh. 6.3 - Prob. 9EGDQCh. 6.7 - Prob. 1QLQ
Ch. 6.7 - Prob. 2QLQCh. 6.7 - Prob. 3QLQCh. 6.7 - The article mentions that quantum computers will...Ch. 6.8 - Prob. 1SGDQCh. 6.8 - Prob. 2SGDQCh. 6.8 - Prob. 3SGDQCh. 6.8 - Prob. 4SGDQCh. 6.8 - Prob. 5SGDQCh. 6.8 - Prob. 6.1ARQCh. 6.8 - Prob. 6.2ARQCh. 6.8 - Prob. 6.3ARQCh. 6.8 - Prob. 6.4ARQCh. 6.8 - Prob. 6.5ARQCh. 6.8 - Prob. 6.6ARQCh. 6.8 - Prob. 6.7ARQCh. 6.8 - Prob. 6.8ARQCh. 6 - Prob. 6.1UYKCh. 6 - Prob. 6.2UYKCh. 6 - Prob. 6.3UYKCh. 6 - Prob. 6.4UYKCh. 6 - Prob. 6.5UYKCh. 6 - Prob. 6.6UYKCh. 6 - Prob. 6.7CE6Ch. 6 - Prob. 6.8CE6Ch. 6 - Prob. 6.9CE6Ch. 6 - Prob. 6.1CE6Ch. 6 - Prob. 6.11CE6Ch. 6 - Prob. 6.12CE6Ch. 6 - Prob. 6.14CS6Ch. 6 - Prob. 6.15CS6Ch. 6 - Prob. 6.16CS6Ch. 6 - Prob. 6.17CS6Ch. 6 - Prob. 6.18CS6Ch. 6 - Prob. 6.19CS6Ch. 6 - Prob. 6.2CS6Ch. 6 - Prob. 6.21MMLCh. 6 - Prob. 6.22MML
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