Using MIS (9th Edition)
9th Edition
ISBN: 9780134106786
Author: David M. Kroenke, Randall J. Boyle
Publisher: PEARSON
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Expert Solution & Answer
Chapter 6, Problem 6.21MML
Explanation of Solution
Requirement analysis:
In this question it is asked to write a memo to the Falcon Security about the working principle of cloud and the role of standards for today’s cloud processing.
Memo:
To: Joni, Falcon Security
From: XXX
Date: DD/MM/YYYY
Re: Working principles of the Cloud and its standards.
Cloud:
The term cloud can be defined as the process that let the computer resources to be accessed anytime anywhere over the internet.
- The cloud can be represented as the elastic leasing of the various computer resources that are known as the pooled resources that can be accessed over the internet.
Factors of cloud:
The three important factors which makes cloud-hosting better for on-site hosting are as follows:
- Cost.
- The cloud-hosting requires very less capital for implementation.
- Flexibility and adaptability.
- The cloud-hosting contains rapid development and is more flexible and adaptable to accept any growing demands.
- Best of breed security.
- Breed security can encourage all companies, because disasters are common in every organization.
Working method of cloud:
Cloud computing is referred as sharing resources, information, and software via internet. Here information is stored on virtual servers which are maintained and controlled by cloud services vendors...
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The Name and Address Problem
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
Chapter 6 Solutions
Using MIS (9th Edition)
Ch. 6.2 - Prob. 1EGDQCh. 6.2 - Prob. 2EGDQCh. 6.2 - Prob. 3EGDQCh. 6.2 - Prob. 4EGDQCh. 6.2 - Prob. 5EGDQCh. 6.2 - Prob. 6EGDQCh. 6.2 - Prob. 7EGDQCh. 6.2 - Prob. 8EGDQCh. 6.2 - Prob. 9EGDQCh. 6.7 - Prob. 1NNE
Ch. 6.7 - Prob. 2NNECh. 6.7 - Prob. 3NNECh. 6.7 - Prob. 4NNECh. 6.7 - Prob. 5NNECh. 6.7 - Prob. 1SGDQCh. 6.7 - Prob. 2SGDQCh. 6.7 - Prob. 3SGDQCh. 6.7 - Prob. 4SGDQCh. 6.7 - Prob. 5SGDQCh. 6.7 - Prob. 1SJGMCh. 6.7 - Prob. 2SJGMCh. 6.7 - Prob. 3SJGMCh. 6.7 - Prob. 4SJGMCh. 6.7 - Prob. 5SJGMCh. 6.7 - Prob. 6SJGMCh. 6.7 - Prob. 7SJGMCh. 6.7 - Prob. 6.1ARQCh. 6.7 - Prob. 6.2ARQCh. 6.7 - Prob. 6.3ARQCh. 6.7 - Prob. 6.4ARQCh. 6.7 - Prob. 6.5ARQCh. 6.7 - Prob. 6.6ARQCh. 6.7 - Prob. 6.7ARQCh. 6 - Prob. 6.1UYKCh. 6 - Prob. 6.2UYKCh. 6 - Prob. 6.3UYKCh. 6 - Prob. 6.4UYKCh. 6 - Prob. 6.5UYKCh. 6 - Prob. 6.6UYKCh. 6 - Prob. 6.7CE6Ch. 6 - Prob. 6.8CE6Ch. 6 - Prob. 6.9CE6Ch. 6 - Prob. 7.10CE6Ch. 6 - Prob. 6.11CE6Ch. 6 - Prob. 6.13CE6Ch. 6 - Prob. 6.14CS6Ch. 6 - Prob. 6.15CS6Ch. 6 - Prob. 6.16CS6Ch. 6 - Prob. 6.17CS6Ch. 6 - Prob. 6.18CS6Ch. 6 - Prob. 6.19CS6Ch. 6 - Prob. 6.20CS6Ch. 6 - Prob. 6.21MMLCh. 6 - Prob. 6.22MML
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