Study Guide with Student Solutions Manual for Seager/Slabaugh/Hansen's Chemistry for Today: General, Organic, and Biochemistry, 9th Edition
Study Guide with Student Solutions Manual for Seager/Slabaugh/Hansen's Chemistry for Today: General, Organic, and Biochemistry, 9th Edition
9th Edition
ISBN: 9781305968608
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 6, Problem 6.20E
Interpretation Introduction

(a)

Interpretation:

The pressure of 210psi is to be converted to atm.

Concept introduction:

The mathematical expressions used to demonstrate the behavior of gases are known as gas laws. These expressions are used under the several changes like temperature, pressure etc. The use of these expressions helps to understand the behavior of gases changing under a particular condition.

Expert Solution
Check Mark

Answer to Problem 6.20E

The pressure of 210psi is equal to 14.29atm.

Explanation of Solution

The relation between psi and atm is as follows.

1atm=14.7psi

The given pressure of 210psi can be converted to atm as follows.

1atm=14.7psi1psi=1atm14.7psi210psi=1atm14.7psi×210psi=14.29atm

Conclusion

The pressure of 210psi is equal to 14.29atm.

Interpretation Introduction

(b)

Interpretation:

The pressure of 210psi is to be converted to bars.

Concept introduction:

The mathematical expressions used to demonstrate the behavior of gases are known as gas laws. These expressions are used under the several changes like temperature, pressure etc. The use of these expressions helps to understand the behavior of gases changing under a particular condition.

Expert Solution
Check Mark

Answer to Problem 6.20E

The pressure of 210psi is equal to 14.4bar.

Explanation of Solution

The relation between psi and atm is as follows.

1atm=14.7psi

The relation between bars and atm is as follows.

1atm=1.01bar

Use above two relations and calculate the given pressure in bars as follows.

1atm=14.7psi1psi=1atm14.7psi×1.01bar1atm210psi=1atm14.7psi×1.01bar1atm×210psi=14.4bar

Conclusion

The pressure of 210psi is equal to 14.4bar.

Interpretation Introduction

(c)

Interpretation:

The pressure of 210psi is to be converted to mmHg.

Concept introduction:

The mathematical expressions used to demonstrate the behavior of gases are known as gas laws. These expressions are used under the several changes like temperature, pressure etc. The use of these expressions helps to understand the behavior of gases changing under a particular condition.

Expert Solution
Check Mark

Answer to Problem 6.20E

The pressure of 210psi is equal to 1.09×104mmHg.

Explanation of Solution

The relation between mmHg and atm is as follows.

1atm=760mmHg

The relation between psi and atm is as follows.

1atm=14.7psi

Use above two relations and calculate the given pressure in mmHg as follows.

1atm=14.7psi1psi=1atm14.7psi×760mmHg1atm210psi=1atm14.7psi×760mmHg1atm×210psi=1.09×104mmHg

Conclusion

The pressure of 210psi is equal to 1.09×104mmHg.

Interpretation Introduction

(d)

Interpretation:

The pressure of 210psi is to be converted to in.Hg.

Concept introduction:

The mathematical expressions used to demonstrate the behavior of gases are known as gas laws. These expressions are used under the several changes like temperature, pressure etc. The use of these expressions helps to understand the behavior of gases changing under a particular condition.

Expert Solution
Check Mark

Answer to Problem 6.20E

The pressure of 210psi is equal to 427.14in.Hg.

Explanation of Solution

The relation between in.Hg and atm is as follows.

1atm=29.9in.Hg

The relation between psi and atm is as follows.

1atm=14.7psi

Use above two relations and calculate the given pressure in in.Hg as follows.

1atm=14.7psi1psi=1atm14.7psi×29.9in.Hg1atm210psi=1atm14.7psi×29.9in.Hg1atm×210psi=427.14in.Hg

Conclusion

The pressure of 210psi is equal to 427.14in.Hg.

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Chapter 6 Solutions

Study Guide with Student Solutions Manual for Seager/Slabaugh/Hansen's Chemistry for Today: General, Organic, and Biochemistry, 9th Edition

Ch. 6 - Prob. 6.11ECh. 6 - Prob. 6.12ECh. 6 - Explain each of the following observations using...Ch. 6 - Prob. 6.14ECh. 6 - The following statements are best associated with...Ch. 6 - Prob. 6.16ECh. 6 - Prob. 6.17ECh. 6 - Prob. 6.18ECh. 6 - Prob. 6.19ECh. 6 - Prob. 6.20ECh. 6 - Prob. 6.21ECh. 6 - Convert each of the following temperatures from...Ch. 6 - Prob. 6.23ECh. 6 - Prob. 6.24ECh. 6 - A 200.mL sample of oxygen gas is collected at...Ch. 6 - A 200.mL sample of nitrogen gas is collected at...Ch. 6 - Prob. 6.27ECh. 6 - Prob. 6.28ECh. 6 - What volume in liters of air measured at 1.00atm...Ch. 6 - What volume in liters of air measured at 1.00atm...Ch. 6 - Prob. 6.31ECh. 6 - Prob. 6.32ECh. 6 - Prob. 6.33ECh. 6 - Prob. 6.34ECh. 6 - A sample of gas has a volume of 375mL at 27C. The...Ch. 6 - What volume of gas in liters at 120.C must be...Ch. 6 - Prob. 6.37ECh. 6 - Prob. 6.38ECh. 6 - Prob. 6.39ECh. 6 - A helium balloon was partially filled with...Ch. 6 - You have a 1.50-L balloon full of air at 30.C. To...Ch. 6 - Prob. 6.42ECh. 6 - What minimum pressure would a 250.-mL aerosol can...Ch. 6 - Prob. 6.44ECh. 6 - Prob. 6.45ECh. 6 - Prob. 6.46ECh. 6 - Prob. 6.47ECh. 6 - Prob. 6.48ECh. 6 - Prob. 6.49ECh. 6 - The pressure gauge of a steel cylinder of methane...Ch. 6 - Suppose 12.0g of dry ice (solidCO2) was placed in...Ch. 6 - Prob. 6.52ECh. 6 - Prob. 6.53ECh. 6 - A sample of gaseous methyl ether has a mass of...Ch. 6 - A sample of gaseous nitrogen oxide is found to...Ch. 6 - A sample of gas weighs 0.176g and has a volume of...Ch. 6 - Prob. 6.57ECh. 6 - Prob. 6.58ECh. 6 - Prob. 6.59ECh. 6 - Prob. 6.60ECh. 6 - Prob. 6.61ECh. 6 - Prob. 6.62ECh. 6 - Prob. 6.63ECh. 6 - Classify each of the following processes as...Ch. 6 - Classify each of the following processes as...Ch. 6 - Prob. 6.66ECh. 6 - Prob. 6.67ECh. 6 - Prob. 6.68ECh. 6 - Prob. 6.69ECh. 6 - Prob. 6.70ECh. 6 - Prob. 6.71ECh. 6 - Prob. 6.72ECh. 6 - Prob. 6.73ECh. 6 - Prob. 6.74ECh. 6 - Prob. 6.75ECh. 6 - Using the specific heat data of Table 6.8,...Ch. 6 - Using the specific heat data of Table 6.8,...Ch. 6 - Prob. 6.78ECh. 6 - Prob. 6.79ECh. 6 - Liquid Freon (CCl2F2) is used as a refrigerant. It...Ch. 6 - Prob. 6.81ECh. 6 - What is the density of argon gas in g/mL at STP?Ch. 6 - Prob. 6.83ECh. 6 - Prob. 6.84ECh. 6 - Prob. 6.85ECh. 6 - Prob. 6.86ECh. 6 - Prob. 6.87ECh. 6 - Prob. 6.88ECh. 6 - Prob. 6.89ECh. 6 - Prob. 6.90ECh. 6 - Prob. 6.91ECh. 6 - Prob. 6.92ECh. 6 - Refer to Figure 6.12 and answer the question....Ch. 6 - Prob. 6.94ECh. 6 - Prob. 6.95ECh. 6 - Definite shape and definite volume best describes...Ch. 6 - Prob. 6.97ECh. 6 - Prob. 6.98ECh. 6 - Prob. 6.99ECh. 6 - Which of the following indicates the relative...Ch. 6 - Prob. 6.101ECh. 6 - Prob. 6.102ECh. 6 - What are the differentiating factors between...Ch. 6 - Prob. 6.104ECh. 6 - Prob. 6.105ECh. 6 - When a vapor condenses into a liquid: a.it absorbs...Ch. 6 - Prob. 6.107ECh. 6 - Prob. 6.108ECh. 6 - Prob. 6.109ECh. 6 - Prob. 6.110ECh. 6 - Prob. 6.111ECh. 6 - Prob. 6.112ECh. 6 - How much heat is required to raise the temperature...Ch. 6 - Prob. 6.115ECh. 6 - Prob. 6.116ECh. 6 - Prob. 6.117ECh. 6 - Prob. 6.118ECh. 6 - Prob. 6.119ECh. 6 - Prob. 6.120ECh. 6 - Prob. 6.121ECh. 6 - Prob. 6.122ECh. 6 - Prob. 6.123ECh. 6 - Prob. 6.124ECh. 6 - Prob. 6.125E
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