Define each of the following terms:
- dynamic view
- correlated subquery
- materialized view
- base table
- Join
- equi-join
- self join
- outer join
- virtualized table
(a)
Define Dynamic View.
Explanation of Solution
Dynamic view is not a temporary table and its definition is stored in the system catalog. The content of this view is materialized as a result of an SQL query that uses the view.
(b)
Define Correlated Subquery.
Explanation of Solution
In SQL, Correlated subquery is a subquery that processes the inner query depending on the data from the outer query.
(c)
Define Materialized View.
Explanation of Solution
Materialized view is different from the dynamic view. It is stored on a disk and is refreshed when used or at some intervals. Copies of data is created in the same way as dynamic view.
(d)
Define Base Table.
Explanation of Solution
Base Table is a table from relational data model that contains the inserted raw data. These tables are correspond to those relations which are identified in the conceptual schema of database.
(e)
Define Join.
Explanation of Solution
Join is a relational operation that is used to combine two tables with a common domain into a single view or table.
(f)
Define Equi Join.
Explanation of Solution
Equi-join is a form of join in which the joining is performed on the basis of the equality between values in the columns that are common. Those common columns appear in the result table redundantly.
(g)
Define Self Join.
Explanation of Solution
Sometimes a join requires match of rows in a table with other rows in that same table which means joining of table with itself. This is known as self join.
(h)
Define Outer Join.
Explanation of Solution
Outer join is a form of join in which those rows are not included in the resulting table that do not have similar values in the common columns.
(i)
Define Virtualized Table.
Explanation of Solution
Virtualized tables are not maintained as the tables with real data. These are constructed automatically as the requirement of a DBMS.
Want to see more full solutions like this?
Chapter 6 Solutions
MODERN DATABASE MGMT.(PEARSON CHANNEL)
Additional Engineering Textbook Solutions
Computer Science: An Overview (13th Edition) (What's New in Computer Science)
Database Concepts (8th Edition)
Introduction To Programming Using Visual Basic (11th Edition)
Starting Out with C++ from Control Structures to Objects (9th Edition)
SURVEY OF OPERATING SYSTEMS
Concepts Of Programming Languages
- Add a timer in the following code. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long elapsedTime; public GameGUI(Labyrinth labyrinth, Player player, Dragon dragon) { this.labyrinth = labyrinth; this.player = player; this.dragon = dragon; String playerName = JOptionPane.showInputDialog("Enter your name:"); player.setName(playerName); elapsedTime = 0; timer = new Timer(1000, e -> { elapsedTime++; repaint(); }); timer.start(); } @Override protected void paintComponent(Graphics g) { super.paintComponent(g); int cellSize = Math.min(getWidth() / labyrinth.getSize(), getHeight() / labyrinth.getSize());}arrow_forwardChange the following code so that when player wins the game, the game continues by creating new GameGUI with the same player. However the player's starting position is same, everything else should be reseted. public static void main(String[] args) { Labyrinth labyrinth = new Labyrinth(10); Player player = new Player(9, 0); Random rand = new Random(); Dragon dragon = new Dragon(rand.nextInt(10), 9); JFrame frame = new JFrame("Labyrinth Game"); GameGUI gui = new GameGUI(labyrinth, player, dragon); frame.setLayout(new BorderLayout()); frame.setSize(600, 600); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.add(gui, BorderLayout.CENTER); frame.pack(); frame.setResizable(false); frame.setVisible(true); } public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long…arrow_forwardCreate a menu item which restarts the game. Also add a timer, which counts the elapsed time since the start of the game level. When the restart is pressed, the restarted game should ask the player' name (in the GameGUI constructor) and set the score of player to 0 (player.setScore(0)), and the timer should restart again. And create a logic so that if the player loses his life (checkGame if the condition is false), then save this number together with his name into two variables. And display two buttons where one quits the game altogether (System.exit(0)) and the other restarts the game. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private final ImageIcon playerIcon = new ImageIcon("data/images/player.png"); private final ImageIcon dragonIcon = new ImageIcon("data/images/dragon.png"); private final ImageIcon wallIcon = new ImageIcon("data/images/wall.png"); private final ImageIcon…arrow_forward
- Please original work Analyze the complexity issues of processing big data What are five complexities and talk about the reasons they make the implementation complex. Please cite in text references and add weblinksarrow_forwardCreate a Database in JAVA Netbeans that saves name of the player and how many labyrinths did the player solve. Record the number of how many labyrinths did the player solve, and if he loses his life, then save this number together with his name into the database. Create a menu item, which displays a highscore table of the players for the 10 best scores public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private void checkGameState() { if (player.getX() == 0 && player.getY() == labyrinth.getSize() - 1) { JOptionPane.showMessageDialog(this, "You escaped! Congratulations!"); System.exit(0); } if (Math.abs(player.getX() - dragon.getX()) <= 1 && Math.abs(player.getY() - dragon.getY()) <= 1) { JOptionPane.showMessageDialog(this, "The dragon caught you! Game Over."); System.exit(0); } } } public…arrow_forwardCreate a Database in JAVA OOP that saves name of the player and how many labyrinths did the player solve. Record the number of how many labyrinths did the player solve, and if he loses his life, then save this number together with his name into the database. Create a menu item, which displays a highscore table of the players for the 10 best scores. Also, create a menu item which restarts the game. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private void checkGameState() { if (player.getX() == 0 && player.getY() == labyrinth.getSize() - 1) { JOptionPane.showMessageDialog(this, "You escaped! Congratulations!"); System.exit(0); } if (Math.abs(player.getX() - dragon.getX()) <= 1 && Math.abs(player.getY() - dragon.getY()) <= 1) { JOptionPane.showMessageDialog(this, "The dragon caught you! Game Over.");…arrow_forward
- Change the following code so that the player can see only the neighboring fields at a distance of 3 units. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private final ImageIcon playerIcon = new ImageIcon("data/images/player.png"); private final ImageIcon dragonIcon = new ImageIcon("data/images/dragon.png"); private final ImageIcon wallIcon = new ImageIcon("data/images/wall.png"); private final ImageIcon emptyIcon = new ImageIcon("data/images/empty.png"); public GameGUI(Labyrinth labyrinth, Player player, Dragon dragon) { this.labyrinth = labyrinth; this.player = player; this.dragon = dragon; setFocusable(true); addKeyListener(new KeyAdapter() { @Override public void keyPressed(KeyEvent e) { char move = switch (e.getKeyCode()) { case KeyEvent.VK_W -> 'W'; case…arrow_forwardQ/ Fill in the table below with the correct answers for the network devices and components required, then draw the topology diagram for the network of this three-story building: I want a drawing Cisco Packet tracer Ground Floor: This floor will house the main server room, reception area, and a few conference rooms. The server room should contain the core network devices that will connect the entire building. The reception area and conference rooms need network access require access for mobile devices for visitors and guests with devices. First Floor: This floor is dedicated to offices with workstations, each needing reliable network connectivity for staff computers, IP phones, IP camera, and printers. Second Floor (Education Department): This floor consists of educational spaces requiring controlled internet access. Only the educational website (https://uokerbala.edu.iq) should be accessible, with all other sites restricted.. Device Media type Location floor Type of IP Static/dynamic…arrow_forwardProblem Statement You are working as a Devops Administrator. Y ou’ve been t asked to deploy a multi - tier application on Kubernetes Cluster. The application is a NodeJS application available on Docker Hub with the following name: d evopsedu/emp loyee This Node JS application works with a mongo database. MongoDB image is available on D ockerHub with the following name: m ongo You are required to deploy this application on Kubernetes: • NodeJS is available on port 8888 in the container and will be reaching out to por t 27017 for mongo database connection • MongoDB will be accepting connections on port 27017 You must deploy this application using the CL I . Once your application is up and running, ensure you can add an employee from the NodeJS application and verify by going to Get Employee page and retrieving your input. Hint: Name the Mongo DB Service and deployment, specifically as “mongo”.arrow_forward
- I need help in server client project. It is around 1200 lines of code in both . I want to meet with the expert online because it is complicated. I want the server send a menu to the client and the client enters his choice and keep on this until the client chooses to exit . the problem is not in the connection itself as far as I know.I tried while loops but did not work. please help its emergentarrow_forwardI need help in my server client in C languagearrow_forwardExercise docID document text docID document text 1 hot chocolate cocoa beans 7 sweet sugar 2345 9 cocoa ghana africa 8 sugar cane brazil beans harvest ghana 9 sweet sugar beet cocoa butter butter truffles sweet chocolate 10 sweet cake icing 11 cake black forest Clustering by k-means, with preprocessing tokenization, term weighting TFIDF. Manhattan Distance. Number of cluster is 2. Centroid docID 2 and docID 9.arrow_forward
- Database Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781305627482Author:Carlos Coronel, Steven MorrisPublisher:Cengage LearningDatabase Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781285196145Author:Steven, Steven Morris, Carlos Coronel, Carlos, Coronel, Carlos; Morris, Carlos Coronel and Steven Morris, Carlos Coronel; Steven Morris, Steven Morris; Carlos CoronelPublisher:Cengage Learning
- A Guide to SQLComputer ScienceISBN:9781111527273Author:Philip J. PrattPublisher:Course Technology PtrProgramming with Microsoft Visual Basic 2017Computer ScienceISBN:9781337102124Author:Diane ZakPublisher:Cengage Learning