EBK USING MIS
10th Edition
ISBN: 8220103633635
Author: KROENKE
Publisher: YUZU
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Chapter 6, Problem 6.12CE6
Explanation of Solution
Cloud Service:
The term cloud can be defined as the process that led the computer resources to be accessed anytime anywhere over the internet. The cloud can be represented as the elastic leasing of the various computer resources that are known as the pooled resources that can be accessed over the internet.
Factors of cloud:
The three important factors which makes cloud-hosting better for on-site hosting are as follows:
- It’s cost.
- The cloud-hosting requires very less capital for implementation.
- Flexibility and adaptability.
- The cloud-hosting contains rapid development and is more flexible and adaptable to accept any growing demands.
- Best of breed security.
- Breed security can encourage all companies, because disasters are common in every organization.
Posture of statement for business professionals to take:
- With respect to Cloud, business professionals will soon take an important decision.
- The cloud becomes more popular among several business, it seems that being a new company will be easier than adapting an existing “Independent Software Vendor (ISV)”...
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D. S. Malik, Data Structures Using C++, 2nd Edition, 2010
Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
I would like to know the main features about the following 3 key concepts:1. Backup Domain Controller (BDC)2. Access Control List (ACL)3. Dynamic Memory
Chapter 6 Solutions
EBK USING MIS
Ch. 6.3 - Prob. 1EGDQCh. 6.3 - Prob. 2EGDQCh. 6.3 - Prob. 3EGDQCh. 6.3 - Prob. 4EGDQCh. 6.3 - Prob. 5EGDQCh. 6.3 - Prob. 6EGDQCh. 6.3 - Prob. 7EGDQCh. 6.3 - Prob. 8EGDQCh. 6.3 - Prob. 9EGDQCh. 6.7 - Prob. 1QLQ
Ch. 6.7 - Prob. 2QLQCh. 6.7 - Prob. 3QLQCh. 6.7 - The article mentions that quantum computers will...Ch. 6.8 - Prob. 1SGDQCh. 6.8 - Prob. 2SGDQCh. 6.8 - Prob. 3SGDQCh. 6.8 - Prob. 4SGDQCh. 6.8 - Prob. 5SGDQCh. 6.8 - Prob. 6.1ARQCh. 6.8 - Prob. 6.2ARQCh. 6.8 - Prob. 6.3ARQCh. 6.8 - Prob. 6.4ARQCh. 6.8 - Prob. 6.5ARQCh. 6.8 - Prob. 6.6ARQCh. 6.8 - Prob. 6.7ARQCh. 6.8 - Prob. 6.8ARQCh. 6 - Prob. 6.1UYKCh. 6 - Prob. 6.2UYKCh. 6 - Prob. 6.3UYKCh. 6 - Prob. 6.4UYKCh. 6 - Prob. 6.5UYKCh. 6 - Prob. 6.6UYKCh. 6 - Prob. 6.7CE6Ch. 6 - Prob. 6.8CE6Ch. 6 - Prob. 6.9CE6Ch. 6 - Prob. 6.1CE6Ch. 6 - Prob. 6.11CE6Ch. 6 - Prob. 6.12CE6Ch. 6 - Prob. 6.14CS6Ch. 6 - Prob. 6.15CS6Ch. 6 - Prob. 6.16CS6Ch. 6 - Prob. 6.17CS6Ch. 6 - Prob. 6.18CS6Ch. 6 - Prob. 6.19CS6Ch. 6 - Prob. 6.2CS6Ch. 6 - Prob. 6.21MMLCh. 6 - Prob. 6.22MML
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