Given the following information, construct a Born-’Habercycle to calculate the lattice energy of CrCl 2 I ( s ) : Net energy change for the formation of CrCl 2 I ( s ) = − 42 0 kJ/mol Bond dissociation energy for Cl 2 ( g ) = + 243 kJ/mol Bond dissociation energy for I 2 ( g ) = + 151 kJ/mol Heat of sublimation for I 2 ( s ) = + 62 kJ/mol Heat of sublimation for Cr ( s ) = + 397 kJ/mol E i1 for Cr ( g ) = 652 kJ/mol E i2 for Cr ( g ) = 1588 kJ/mol E i3 for Cr ( g ) = 2882 kJ/mol E ea for Cl ( g ) = − 349 kJ/mol E ea for I ( g ) = − 295 kJ/mol
Given the following information, construct a Born-’Habercycle to calculate the lattice energy of CrCl 2 I ( s ) : Net energy change for the formation of CrCl 2 I ( s ) = − 42 0 kJ/mol Bond dissociation energy for Cl 2 ( g ) = + 243 kJ/mol Bond dissociation energy for I 2 ( g ) = + 151 kJ/mol Heat of sublimation for I 2 ( s ) = + 62 kJ/mol Heat of sublimation for Cr ( s ) = + 397 kJ/mol E i1 for Cr ( g ) = 652 kJ/mol E i2 for Cr ( g ) = 1588 kJ/mol E i3 for Cr ( g ) = 2882 kJ/mol E ea for Cl ( g ) = − 349 kJ/mol E ea for I ( g ) = − 295 kJ/mol
Solution Summary: The author describes the steps required to draw Born-Haber cycle of ionic solids from its constituent elements.
Given the following information, construct a Born-’Habercycle to calculate the lattice energy of
CrCl
2
I
(
s
)
:
Net energy change for the formation of CrCl
2
I
(
s
)
=
−
42
0
kJ/mol
Bond dissociation energy for Cl
2
(
g
)
=
+
243 kJ/mol
Bond dissociation energy for I
2
(
g
)
=
+
151 kJ/mol
Heat of sublimation for I
2
(
s
)
=
+
62 kJ/mol
Heat of sublimation for Cr
(
s
)
=
+
397 kJ/mol
E
i1
for Cr
(
g
)
=
652 kJ/mol
E
i2
for Cr
(
g
)
=
1588 kJ/mol
E
i3
for Cr
(
g
)
=
2882 kJ/mol
E
ea
for Cl
(
g
)
=
−
349 kJ/mol
E
ea
for I
(
g
)
=
−
295 kJ/mol
>
Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating
the reactants?
esc
?
A
O
O
•If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like.
• If your answer is no, check the box under the drawing area instead.
olo
18
Ar
Explanation
Check
BB
Click and drag to start drawing a structure.
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Name the structure
>
For each pair of substrates below, choose the one that will react faster in a substitution reaction, assuming that:
1. the rate of substitution doesn't depend on nucleophile concentration and
2. the products are a roughly 50/50 mixture of enantiomers.
Substrate A
Substrate B
Faster Rate
X
CI
(Choose one)
(Choose one)
CI
Br
Explanation
Check
Br
(Choose one)
C
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A
F10
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