Chapter 6, Problem 5PE

Interpretation Introduction

Interpretation:

The energy required to raise the temperature of $255\text{ g}$ of water from ${\text{25 to 30 }}^{\text{o}}\text{C}$ in joules, kilojoules, calories, and kilocalories is to be calculated.

Concept Introduction:

Each material requires different amount of energy, which depends on the mass of the material, specific heat capacity, and the change in its temperature.

Joule is the SI unit of energy, and is defined as the energy required to raise the temperature of $1\text{ kg}$ of water by $\text{1 }°\text{C}$, whereas that for $1\text{ g}$ of water gives the value in calories. 1 calorie is equal to $4.184\text{ J}$.

Conversion factor is as

$\frac{\text{4}\text{.184 J}}{1\text{cal}}$