EBK ELECTRIC CIRCUITS
11th Edition
ISBN: 9780134747224
Author: Riedel
Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)
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Chapter 6, Problem 5P
a.
To determine
Derive the expression for the voltage across the inductor for the range
b.
To determine
Calculate the time that is greater than zero when the power at inductor terminals is zero.
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-E1 + VR1 + VR4 – E2 + VR3 = 0 -------> Loop 1 (a)
R1(I1) + R4(I1 – I2) + R3(I1) = E1 + E2 ------> Loop 1 (b)
R1(I1) + R4(I1) - R4(I2) + R3(I1) = E1 + E2 ------> Loop 1 (c)
(R1 + R3 + R4) (I1) - R4(I2) = E1 + E2 ------> Loop 1 (d)
Now that we have loop 1 equation will procced on finding the equation of I2 current loop. However, a reminder that because we are going in a clockwise direction, it goes against the direction of the current. As such we will get an equation for the matrix that will be:
E2 – VR4 – VR2 + E3 = 0 ------> Loop 2 (a)
-R4(I2 – I1) -R2(I2) = -E2 – E3 ------> Loop 2 (b)
-R4(I2) + R4(I1) - R2(I2) = -E2 – E3 -----> Loop 2 (c)
R4(I1) – (R4 + R2)(I2) = -E2 – E3 -----> Loop 2 (d)
These two equations will be implemented to the matrix formula I = inv(A) * b
R11 R12
(R1 + R3 + R4)
-R4
-R4
R4 + R2
10.2 For each of the following groups of sources, determineif the three sources constitute a balanced source, and if it is,determine if it has a positive or negative phase sequence.(a) va(t) = 169.7cos(377t +15◦) Vvb(t) = 169.7cos(377t −105◦) Vvc(t) = 169.7sin(377t −135◦) V(b) va(t) = 311cos(wt −12◦) Vvb(t) = 311cos(wt +108◦) Vvc(t) = 311cos(wt +228◦) V(c) V1 = 140 −140◦ VV2 = 114 −20◦ VV3 = 124 100◦ V
Apply single-phase equivalency to determine the linecurrents in the Y-D network shown in Fig. P10.13. The loadimpedances are Zab = Zbc = Zca = (25+ j5) W
Chapter 6 Solutions
EBK ELECTRIC CIRCUITS
Ch. 6.1 - The current source in the circuit shown generates...Ch. 6.2 - Prob. 2APCh. 6.2 - The current in the capacitor of Assessment Problem...Ch. 6.3 - The initial values of i1 and i2 in the circuit...Ch. 6.3 - Prob. 5APCh. 6.4 - Write a set of mesh-current equations for the...Ch. 6.5 - Consider the magnetically coupled coils described...Ch. 6 - Prob. 1PCh. 6 - The voltage at the terminals of the 200 μH...Ch. 6 - The triangular current pulse shown in Fig. P6.3 is...
Ch. 6 - The current in a 200 mH inductor is
The voltage...Ch. 6 - The current in a 20 mH inductor is known to...Ch. 6 - Assume in Problem 6.5 that the value of the...Ch. 6 - Evaluate the integral
for Example 6.2. Comment on...Ch. 6 - Find the inductor current in the circuit in Fig....Ch. 6 - The current in and the voltage across a 5 H...Ch. 6 - The current in the 2.5 mH inductor in Fig. P6.11...Ch. 6 - Initially there was no energy stored in the 5 H...Ch. 6 - The voltage across a 5 μF capacitor is known to...Ch. 6 - The triangular voltage pulse shown in Fig. P6.15...Ch. 6 - The expressions for voltage, power, and energy...Ch. 6 - A 20µF capacitor is subjected to a voltage pulse...Ch. 6 - The initial voltage on the 0.5 μF capacitor shown...Ch. 6 - The current shown in Fig. P6.20 is applied to a...Ch. 6 - The rectangular-shaped current pulse shown in Fig....Ch. 6 - Use realistic inductor values from Appendix H to...Ch. 6 - For the circuit shown in Fig. P6.24, how many...Ch. 6 - The two parallel inductors in Fig. P6.26 are...Ch. 6 - Derive the equivalent circuit for a series...Ch. 6 - Derive the equivalent circuit for a parallel...Ch. 6 - Use realistic capacitor values from Appendix H to...Ch. 6 - Prob. 30PCh. 6 - The two series-connected capacitors in Fig. P6.31...Ch. 6 - The four capacitors in the circuit in Fig, P6.32...Ch. 6 - For the circuit in Fig. P6.32, calculate
the...Ch. 6 - At t = 0. a series-connected capacitor and...Ch. 6 - The current in the circuit in Fig. P6.35 is known...Ch. 6 - Show that the differential equations derived in...Ch. 6 - Prob. 37PCh. 6 - Prob. 38PCh. 6 - Let υg represent the voltage across the current...Ch. 6 - Prob. 40PCh. 6 - Prob. 41PCh. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45PCh. 6 - Prob. 46PCh. 6 - Prob. 47PCh. 6 - Prob. 48PCh. 6 - The self-inductances of two magnetically coupled...Ch. 6 - Prob. 50PCh. 6 - Prob. 51PCh. 6 - Prob. 52PCh. 6 - Prob. 53P
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- 10.8 In the network of Fig. P10.8, Za = Zb = Zc = (25+ j5) W.Determine the line currents.arrow_forwardUsing D flip-flops, design a synchronous counter. The counter counts in the sequence 1,3,5,7, 1,7,5,3,1,3,5,7,.... when its enable input x is equal to 1; otherwise, the counter count 0. Present state Next state x=0 Next state x=1 Output SO 52 S1 1 S1 54 53 3 52 53 S2 56 51 0 $5 5 54 S4 53 0 55 58 57 7 56 56 55 0 57 S10 59 1 58 58 S7 0 59 S12 S11 7 $10 $10 59 0 $11 $14 $13 5 $12 S12 $11 0 513 $15 SO 3 S14 $14 S13 0 $15 515 SO 0 Explain how to get the table step by step with drawing the state diagram and finding the Karnaugh map.arrow_forwardFor the oscillator resonance circuit shown in Fig. (5), derive the oscillation frequency Feedback and open-loop gains. L₁ 5 mH (a) ell +10 V R₁ ww R3 S C2 HH 1 με 1000 pF 100 pF R₂ 1 με RA H (b) +9 V R4 CA 470 pF C₁ R3 HH 1 με R₁ ww L₁ 000 1.5 mH R₂ ww Hi 1 μF L2 m 10 mHarrow_forward
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- A) Calculate the efficiency of the test transformer at the resistive loads (X-25%, 50%, 75%, 100%, 125% full load). B) From part (A) draw the plot (efficiency Vs power output) of the transformer. C) Discuss the plot of part (B).arrow_forwarda- Determine fH; and Ho b- Find fg and fr. c- Sketch the frequency response for the high-frequency region using a Bode plot and determine the cutoff frequency. Ans: 277.89 KHz; 2.73 MHz; 895.56 KHz; 107.47 MHz. 14V Cw=5pF Cwo-8pF Coc-12 pF 5.6kQ Ch. 40. pF C-8pF 68kQ 0.47µF Vo 0.82 kQ V₁ B=120 0.47µF www 3.3kQ 10kQ 1.2kQ =20µF Narrow_forwardUsing D flip-flops, design a synchronous counter. The counter counts in the sequence 1,3,5,7, 1,7,5,3,1,3,5,7,.... when its enable input x is equal to 1; otherwise, the counter. This counter is for individual settings only need the state diagram and need the state table to use 16 states from So to S15.arrow_forward
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