Explanation Given: Matrix: ( 1 3 − 2 − 1 0 1 1 2 − 1 − 1 1 − 1 1 − 1 − 3 − 2 ) Calculation: To calculate the inverse of the provided matrix, first make augmented matrix as, [ A I ] where I is the identity matrix of order same as provided matrix. So, ( 1 3 − 2 − 1 1 0 0 0 0 1 1 2 0 1 0 0 − 1 − 1 1 − 1 0 0 1 0 1 − 1 − 3 − 2 0 0 0 1 ) Now, change the matrix in left hand side into identity matrix by applying row transformations on the augmented matrix. Use the transformation, R 3 → R 3 + R 1 : ( 1 3 − 2 − 1 1 0 0 0 0 1 1 2 0 1 0 0 0 2 − 1 − 2 1 0 1 0 1 − 1 − 3 − 2 0 0 0 1 ) Use the transformation, R 4 → R 4 − ( R 1 ) : ( 1 3 − 2 − 1 1 0 0 0 0 1 1 2 0 1 0 0 0 2 − 1 − 2 1 0 1 0 0 − 4 − 1 − 1 − 1 0 0 1 ) Use the transformation, R 1 → R 1 − 3 R 2 : ( 1 0 − 5 − 7 1 − 3 0 0 0 1 1 2 0 1 0 0 0 2 − 1 − 2 1 0 1 0 0 − 4 − 1 − 1 − 1 0 0 1 ) Use the transformation R 3 → R 3 − 2 R 2 ( 1 0 − 5 − 7 1 − 3 0 0 0 1 1 2 0 1 0 0 0 0 − 3 − 6 1 − 2 1 0 0 − 4 − 1 − 1 − 1 0 0 1 ) Use the transformation, R 4 → R 4 − ( − 4 R 2 ) : ( 1 0 − 5 − 7 1 − 3 0 0 0 1 1 2 0 1 0 0 0 0 − 3 − 6 1 − 2 1 0 0 0 3 7 − 1 4 0 1 ) Use the transformation, R 3 → 1 − 3 R 3 : ( 1 0 − 5 − 7 1 − 3 0 0 0 1 1 2 0 1 0 0 0 0 1 2 − 1 3 2 3 − 1 3 0 0 0 3 7 − 1 4 0 1 ) Use the transformation, R 1 → R 1 − ( ( − 5 ) R 3 ) : ( 1 0 0 3 − 2 3 1 3 − 5 3 0 <

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Chapter 6, Problem 59RE

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To calculate: The inverse of the matrices (13−2−10112−1−11−11−1−3−2).

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Chapter 6, Problem 58RE

Chapter 6, Problem 60RE

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EBK MATHEMATICS WITH APPLICATIONS IN TH

Ch. 6.1 - Checkpoint1 Use the substitution method tosolve...Ch. 6.1 - Checkpoint 2 Use the elimination method to solve...Ch. 6.1 - Checkpoint 3 Solve the system of equations . Draw...Ch. 6.1 - Checkpoint 4 Solve the following system: Ch. 6.1 - Checkpoint 5 Solve the system Draw the graph of...Ch. 6.1 - Prob. 6CP Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Use substitution to solve each system. (See...Ch. 6.1 - Use substitution to solve each system. (See...

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The inverse of the matrices ( 1 3 − 2 − 1 0 1 1 2 − 1 − 1 1 − 1 1 − 1 − 3 − 2 ) .

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To calculate: The inverse of the matrices (13−2−10112−1−11−11−1−3−2).

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Chapter 6 Solutions