Explanation Given Info: Mass of an engine is m = 3.00 × 10 4 kg and acceleration of ship is a = 49.0 m/s 2 , exhaust speed of an engine is v e = 2.50 × 10 3 m/s and instantaneous thrust of a rocket engine is T = 1.47 × 10 6 N . Explanation: Take the net force as instantaneous thrust. The expression for net force by Newton’s Second law is, F n e t = m a F n e t is the net force of an engine. m is the mass of an engine. a is the acceleration of ship. Rewrite the above equation for thrust. T = m a (1) T is the instantaneous thrust of a rocket engine. Substitute 3.00 × 10 4 kg for m and 49.0 m/s 2 for a in equation (1). T = ( 3.00 × 10 4 kg ) ( 49.0 m/s 2 ) = 147 × 10 4 N = 1.47 × 10 6 N The expression for thrust is, T = | v e Δ m Δ t | T is the instantaneous thrust of a rocket engine

11th Edition

ISBN: 9780357683538

Author: SERWAY

Publisher: CENGAGE L

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Chapter 6, Problem 57P

To determine

The burn rate of a fuel in an engine.

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Chapter 6 Solutions

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The burn rate of a fuel in an engine.

Solution Summary: The author explains the burn rate of a fuel in an engine. The expression for net force by Newton’s Second law is, F_net=ma.

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The burn rate of a fuel in an engine.

Chapter 6 Solutions