MAT.SCIENCE+ENGIN.(PERUSALL ACCESS)
MAT.SCIENCE+ENGIN.(PERUSALL ACCESS)
10th Edition
ISBN: 2818440149658
Author: Callister
Publisher: PERUSALL
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Chapter 6, Problem 53QAP

(a)

To determine

The indentation diagonal length of the specimen.

(b)

To determine

The Vickers hardness number of specimen.

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A technology company specializing in IoT solutions for homes and workplaces is looking to strengthen the security of its products. To achieve this, they require expert insights into secure design methodologies, security audits, and best practices for mitigating risks. This report will provide tailored recommendations for their software development team. Key Areas Ensuring security from the initial design phase is essential for developing resilient IoT systems. This section will: Explore various secure design methodologies relevant to IoT. Assess the advantages and limitations of each approach. Recommend an optimal methodology suited to the company’s development workflow. To complement a secure design strategy, regular security audits must be conducted to identify and address vulnerabilities. This section will: Provide an overview of leading security audit methodologies, such as PTES and OWASP. Outline a step-by-step approach to performing an effective security audit. Evaluate…
Question 6: Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the volume of a particular sample of Cl₂ gas is 8.70 L at 895 torr and 24°C. (a) How many grams of Cl₂ are in the sample? ⚫ Atomic mass of CI = 35.453 g/mol • Molar mass of Cl₂ = 2 x 35.453 = 70.906 g/mol Solution: Use the Ideal Gas Law: Step 1: Convert Given Values • Pressure: P = 895 torr → atm PV= = nRT 1 P = 895 × = 1.1789 atm 760 • Temperature: Convert to Kelvin: T24273.15 = 297.15 K • Gas constant: R = 0.0821 L atm/mol. K Volume: V = 8.70 L Step 2: Solve for n . PV n = RT n = (1.1789)(8.70) (0.0821)(297.15) 10.25 n = = 0.420 mol 24.405 Step 3: Calculate Mass of Cl₂ Final Answer: 29.78 g of Cl₂. mass nx M mass= (0.420)(70.906) mass= 29.78 g
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