
Concept explainers
(a)
Interpretation:
A balanced equation of the given reaction should be determined.
Concept Introduction:
In a balanced

Answer to Problem 44QAP
Explanation of Solution
The following unbalanced equation is given:
There is no clear choice for the most complicated molecule. We arbitrarily start with the elements of BaNO3 To balance oxygen, we place a coefficient of 2 before NaNO3. We have got a balanced equation.
(b)
Interpretation:
A balanced equation of the given reaction should be determined.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that present before the compounds are changed but not the subscripts in the formulas.

Answer to Problem 44QAP
Explanation of Solution
The following unbalanced equation is given:
There is no clear choice for the most complicated molecule. We arbitrarily start with the elements of PbCl2 To balance chlorine, we place a coefficient of 2 before KCl. We have got a balanced equation.
(c)
Interpretation:
A balanced equation of the given reaction should be determined.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that present before the compounds are changed but not the subscripts in the formulas.

Answer to Problem 44QAP
Explanation of Solution
The following unbalanced equation is given:
The most complicated molecule is C2 H5 OH because it contains the most elements (three). To balance C, we place a coefficient ot 2 before CO2.
To balance H, we place a coefficient of 3 before H2 O.
Finally, to balance O, we place a coefficient of 3 before O2.
We now have a balanced equation.
(d)
Interpretation:
A balanced equation of the given reaction should be determined.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that present before the compounds are changed but not the subscripts in the formulas.

Answer to Problem 44QAP
Explanation of Solution
The following unbalanced equation is given:
The most complicated molecule is Ca(OH)2 because it contains the most elements (three). We start with hydrogen. To balance H we place a coefficient of 2 before H2 O. We now have a balanced equation.
(e)
Interpretation:
A balanced equation of the given reaction should be determined.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that present before the compounds are changed but not the subscripts in the formulas.

Answer to Problem 44QAP
Explanation of Solution
The following unbalanced equation is given:
There is no clear choice for the most complicated molecule. We arbitrarily start with the elements of SrNO3 To balance oxygen we, place a coefficient ot 2 before HNO3. We have got a balanced equation.
Interpretation:
A balanced equation of the given reaction should be determined.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that present before the compounds are changed but not the subscripts in the formulas.

Answer to Problem 44QAP
Explanation of Solution
The following equation is given:
It can be seen that all the elements are already balanced. Therefore, we have got a balanced equation.
(g)
Interpretation:
A balanced equation of the given reaction should be determined.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that present before the compounds are changed but not the subscripts in the formulas.

Answer to Problem 44QAP
Explanation of Solution
The following unbalanced equation is given:
The most complicated molecule is AsI3. We start with Iodine. To balance Iodine, we place a coefficient ot 3 before I2 and 2 before AsI3
To balance As, we place a coefficient of 2 before As.
We now have a balanced equation.
Interpretation:
A balanced equation of the given reaction should be determined.
Concept Introduction:
In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that present before the compounds are changed but not the subscripts in the formulas.

Answer to Problem 44QAP
Explanation of Solution
The following unbalanced equation is given:
There is no clear choice for the most complicated molecule. We arbitrarily start with the elements of K2 SO4 To balance K, we place a coefficient of 2 before KI.
We can balance the equation by giving I2 a cofficient of ½.
The coffecient should be an integer, therefore we should multiply the equation by 2. We have got a balanced equation.
Want to see more full solutions like this?
Chapter 6 Solutions
Introductory Chemistry: A Foundation
- For Raman spectroscopy/imaging, which statement is not true regarding its disadvantages? a) Limited spatial resolution. b) Short integration time. c) A one-dimensional technique. d) Weak signal, only 1 in 108 incident photons is Raman scattered. e) Fluorescence interference.arrow_forwardUsing a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c. (Please provide a full derivation of the equation for x from the equation for I). d) Calculate x for the 1645 cm-1 bandarrow_forwardI need help with the follloaingarrow_forward
- For a CARS experiment on a Raman band 918 cm-1, if omega1= 1280 nm, calculate the omega2 in wavelength (nm) and the CARS output in wavelength (nm).arrow_forwardI need help with the following questionarrow_forwardFor CARS, which statement is not true regarding its advantages? a) Contrast signal based on vibrational characteristics, no need for fluorescent tagging. b) Stronger signals than spontaneous Raman. c) Suffers from fluorescence interference, because CARS signal is at high frequency. d) Faster, more efficient imaging for real-time analysis. e) Higher resolution than spontaneous Raman microscopy.arrow_forward
- Draw the major product of the Claisen condensation reaction between two molecules of this ester. Ignore inorganic byproducts. Incorrect, 5 attempts remaining 1. NaOCH3/CH3OH 2. Acidic workup Select to Draw O Incorrect, 5 attempts remaining The total number of carbons in the parent chain is incorrect. Review the reaction conditions including starting materials and/or intermediate structures and recount the number of carbon atoms in the parent chain of your structure. OKarrow_forwardUsing a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c d) Calculate x for the 1645 cm-1 bandarrow_forwardConvert 1.38 eV into wavelength (nm) and wavenumber (cm-1) (c = 2.998 x 108 m/s; h = 6.626 x 10-34 J*s).arrow_forward
- Can you help me understand the CBC method on metal bridging by looking at this problem?arrow_forwardA partir de Aluminio y Co(NO3)2ꞏ6H2O, indicar las reacciones a realizar para obtener Azul de Thenard (Al2CoO4).arrow_forwardTo obtain Thenard Blue (Al2CoO4), the following reaction is correct (performed in an oven):Al(OH)3 + Co(OH)2 → Al2CoO4 + 4 H2Oarrow_forward
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning





