Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
8th Edition
ISBN: 9781285199030
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 6, Problem 43QAP
Interpretation Introduction

(a)

Interpretation:

The given chemical equation is to be balanced.

Concept Introduction:

In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

Expert Solution
Check Mark

Answer to Problem 43QAP

2KO2(s)+2H2O(l)2KOH(aq)+O2(g)+H2O2(aq).

Explanation of Solution

The provided reaction is:

KO2(s)+H2O(l)KOH(aq)+O2(g)+H2O2(aq)

In the given equation if we place a coefficient of 2 before KO2 and coefficient 2 to theH2 O that is on the reactant side, and coefficient 2 is added on the product side of KOH, then the atoms are balanced with two potassium, six oxygen atom and four hydrogen atoms giving the balanced equation.

2KO2(s)+2H2O(l)2KOH(aq)+O2(g)+H2O2(aq) g.

Interpretation Introduction

(b)

Interpretation:

The given chemical equation is to be balanced.

Concept Introduction:

In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

Expert Solution
Check Mark

Answer to Problem 43QAP

Fe2O3(s)+6HNO3(aq)2Fe(NO3)3(aq)+3H2O(l).

Explanation of Solution

The given unbalanced equation is:

Fe2O3(s)+HNO3(aq)Fe(NO3)3(aq)+H2O(l)

We start with elements of Fe(NO3)3. To balance Fe, we need to place coefficient 2 before Fe(NO3)3, coefficient 6 before HNO3 and coefficient 3 before H2 O. So we have six hydrogen atoms, two iron, six nitrogen and six hydrogen forming the balanced equation. Thus, the balanced chemical reaction is as follows:

Fe2O3(s)+6HNO3(aq)2Fe(NO3)3(aq)+3H2O(l).

Interpretation Introduction

(c)

Interpretation:

The given chemical equation is to be balanced.

Concept Introduction:

In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

Expert Solution
Check Mark

Answer to Problem 43QAP

4NH3(g)+5O2(g)4NO(g)+6H2O(g).

Explanation of Solution

The given unbalanced equation is:

NH3(g)+O2(g)NO(g)+H2O(g)

We start by balancingNH3. If we place a coefficient 4 before NH3, coefficient5 before O2, coefficient 4 before NO and coefficient 6 before H2 O, then we have four nitrogen atoms, twelve hydrogen atoms, and ten oxygen atoms forming the balanced equation. Thus, the balanced chemical reaction will be as follows:

Interpretation Introduction

(d)

Interpretation:

The given chemical equation is to be balanced.

Concept Introduction:

In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

Expert Solution
Check Mark

Answer to Problem 43QAP

PCl5(l)+4H2O(l)H3PO4(aq)+5HCl(g).

Explanation of Solution

The provided equation is:

PCl5(l)+H2O(l)H3PO4(aq)+HCl(g)

The most complicated molecule is H3PO4 because it contains the greatestnumber of elements. If we place a coefficient of 5 before HCl and 4 before H2 O, then we have one phosphorous atom, five chlorine atom, eight hydrogen atom and four oxygen atom giving the balanced equation. The equation balanced is given as,

PCl5(l)+4H2O(l)H3PO4(aq)+5HCl(g).

Interpretation Introduction

(e)

Interpretation:

The given chemical equation is to be balanced.

Concept Introduction:

In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

Expert Solution
Check Mark

Answer to Problem 43QAP

C2H5OH(l)+3O2(g)2CO2(g)+3H2O(l).

Explanation of Solution

The provided equation is:

C2H5OH(l)+O2(g)CO2(g)+H2O(l)

The most complicated molecule is C2H5OH because it contains the greatestnumber of elements. We place a coefficient of 2 before CO2, 3 before H2 O and 3 before O2 that gives two atoms of carbon, six atoms of hydrogen, and seven atoms of oxygen to form the balanced equation. Thus, the balanced chemical reaction is as follows:

C2H5OH(l)+3O2(g)2CO2(g)+3H2O(l).

Interpretation Introduction

(f)

Interpretation:

The given chemical equation is to be balanced.

Concept Introduction:

In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

Expert Solution
Check Mark

Answer to Problem 43QAP

2CaO(s)+5C(s)2CaC2(s)+CO2(g).

Explanation of Solution

The provided reaction is:

CaO(s)+C(s)CaC2(s)+CO2(g)

If we place a coefficient of 2 before CaO and CaC2 we get,

2CaO(s)+C(s)2CaC2(s)+CO2(g)

We place a coefficient of 5 before C. Now, we have a balanced equation.

2CaO(s)+5C(s)2CaC2(s)+CO2(g).

Interpretation Introduction

(g)

Interpretation:

The given chemical equation is to be balanced.

Concept Introduction:

In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

Expert Solution
Check Mark

Answer to Problem 43QAP

2MoS2(s)+7O2(g)2MoO3(s)+4SO2(g).

Explanation of Solution

The provided reaction is:

MoS2(s)+O2(g)MoO3(s)+SO2(g)

If we place a coefficient of 4 before SO2 and 2 before MoS2, we get:

2MoS2(s)+O2(g)MoO3(s)+4SO2(g)

By placing a coefficient of 2 before MoO3 and 7 before O2, we have a balanced equation.

2MoS2(s)+7O2(g)2MoO3(s)+4SO2(g).

Interpretation Introduction

(h)

Interpretation:

The given chemical equation is to be balanced.

Concept Introduction:

In a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal. To balance an unbalanced equation, the coefficients that are present before the compounds are changed but the subscripts in the formulas are not changed.

Expert Solution
Check Mark

Answer to Problem 43QAP

FeCO3(s)+H2CO3(aq)Fe(HCO3)2(aq).

Explanation of Solution

The provided reaction is:

FeCO3(s)+H2CO3(aq)Fe(HCO3)2(aq)

We see that all the atoms are balanced. Hence, we have a balanced equation.

FeCO3(s)+H2CO3(aq)Fe(HCO3)2(aq).

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Chapter 6 Solutions

Introductory Chemistry: A Foundation

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