Balance each of the following chemical equations. l type='a'> msp; FeCl 3 ( a q ) + KOH ( a q ) → Fe ( OH ) 3 ( s ) + KCl ( a q ) i> Pb ( C 2 H 3 O 2 ) 2 ( a q ) + KI ( a q ) → PbI 2 ( s ) + KC 2 H 3 O 2 ( a q ) i> P 4 O 10 ( s ) + H 2 O ( l ) → H 3 PO 4 ( a q ) i> Li 2 O ( s ) + H 2 O ( l ) → LiOH ( a q ) i> MnO 2 ( s ) + C ( s ) → Mn ( s ) + CO 2 ( g ) i> Sb ( s ) + Cl 2 ( g ) → SbCl 3 ( s ) i> CH 4 ( g ) + H 2 O ( g ) → CO ( g ) + H 2 ( g ) i> FeS ( s ) + HCl ( a q ) → FeCl 2 ( a q ) + H 2 S ( g )
Balance each of the following chemical equations. l type='a'> msp; FeCl 3 ( a q ) + KOH ( a q ) → Fe ( OH ) 3 ( s ) + KCl ( a q ) i> Pb ( C 2 H 3 O 2 ) 2 ( a q ) + KI ( a q ) → PbI 2 ( s ) + KC 2 H 3 O 2 ( a q ) i> P 4 O 10 ( s ) + H 2 O ( l ) → H 3 PO 4 ( a q ) i> Li 2 O ( s ) + H 2 O ( l ) → LiOH ( a q ) i> MnO 2 ( s ) + C ( s ) → Mn ( s ) + CO 2 ( g ) i> Sb ( s ) + Cl 2 ( g ) → SbCl 3 ( s ) i> CH 4 ( g ) + H 2 O ( g ) → CO ( g ) + H 2 ( g ) i> FeS ( s ) + HCl ( a q ) → FeCl 2 ( a q ) + H 2 S ( g )
Solution Summary: The author explains that in a balanced chemical reaction, the number of similar type of elements on both sides of the reaction is equal.
9:27 AM Tue Mar 4
←
Problem 64 of 15
#63%
Submit
Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product
structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s).
Be sure to account for all bond-breaking and bond-making steps.
0:0
0:0
:0:
N.
:0:
:O
:0:
H
H.
:0:
Select to Add Arrows
O
:0:
H
O
:0:
0:0.
S.
H
Select to Add Arrows
S
:0:
:0:
H
H
Order the following organic reactions by relative rate. That is, select '1' next to the reaction that will have the fastest initial rate, select '2' next to the reaction
that will have the next fastest initial rate, and so on. If two reactions will have very similar initial rates, you can select the same number next to both.
If a reaction will have zero or nearly zero initial rate, don't select a number and check the box in the table instead.
Note: the "Nu" in these reactions means "a generic nucleophile."
ملی
CI
:Nu
2
он
3
H
Reaction
Relative Rate
(Choose one) ▼
Nu
:CI:
zero or nearly zero
Nu
:Nu
bi
(Choose one)
zero or nearly zero
: Nu
لی
Nu
:H
(Choose one)
zero or nearly zero
9:12 AM Tue Mar 4
66%
Problem 38 of 15
Submit
Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow
the arrows to draw the product formed in this reaction or mechanistic step(s).
Include all lone pairs and charges as appropriate. Ignore inorganic byproducts.
Br2
FeBrз
H
(+)
Br:
H
: Br----FeBr3
く
a
SU
00
nd
e
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