
(a)
The work done by the force from
(a)

Explanation of Solution
Given:
Mass of the object is
Velocity of the object is
Formula used:
Write expression for work done by the force from
Here,
Write expression for area of square.
Here,
Calculation:
Substitute
Substitute
Conclusion:
Thus, work done by the force is
(b)
The kinetic energy of object at
(b)

Explanation of Solution
Given:
Mass of the object is
Velocity of the object is
Formula used:
Write expression for work done by the force from
Here,
Write expression for area of square.
Here,
Write expression for kinetic energy at
Substitute
Calculation:
Substitute
Substitute
Substitute
Conclusion:
Thus, kinetic energy at
(c)
The speed of object at
(c)

Explanation of Solution
Given:
Mass of the object is
Velocity of the object is
Formula used:
Write expression for velocity at
Calculation:
Substitute
Conclusion:
Thus, the velocity of object is
(d)
The work done on the object from
(d)

Explanation of Solution
Given:
Mass of the object is
Velocity of the object is
Formula used:
Write expression for work done on the object from
Here,
Write expression for area of square.
Here,
Calculation:
Substitute
Substitute
Conclusion:
Thus, work done is
(e)
The speed of object at
(e)

Explanation of Solution
Given:
Mass of the object is
Velocity of the object is
Formula used:
Write expression for kinetic energy at
Substitute
Write expression for velocity at
Calculation:
Substitute
Substitute
Conclusion:
Thus, velocity of the object is
Want to see more full solutions like this?
Chapter 6 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- # E 94 20 13. Time a) What is the frequency of the above wave? b) What is the period? c) Highlight the second cycle d) Sketch the sine wave of the second harmonic of this wave % 7 & 5 6 7 8 * ∞ Y U 9 0 0 P 150arrow_forwardShow work using graphing paperarrow_forwardCan someone help me answer this physics 2 questions. Thank you.arrow_forward
- Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.) a C 3.00 με Hh. 6.00 με 20.0 με HE (a) Find the equivalent capacitance between points a and b. 5.92 HF (b) Calculate the charge on each capacitor, taking AV ab = 16.0 V. 20.0 uF capacitor 94.7 6.00 uF capacitor 67.6 32.14 3.00 µF capacitor capacitor C ☑ με με The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC 32.14 ☑ You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μCarrow_forwardIn the pivot assignment, we observed waves moving on a string stretched by hanging weights. We noticed that certain frequencies produced standing waves. One such situation is shown below: 0 ст Direct Measurement ©2015 Peter Bohacek I. 20 0 cm 10 20 30 40 50 60 70 80 90 100 Which Harmonic is this? Do NOT include units! What is the wavelength of this wave in cm with only no decimal places? If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with NO decimal places)?arrow_forwardFour capacitors are connected as shown in the figure below. (Let C = 12.0 µF.) A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b. (a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V. 20.0 µF capacitor µC 6.00 µF capacitor µC 3.00 µF capacitor µC capacitor C µCarrow_forward
- Two conductors having net charges of +14.0 µC and -14.0 µC have a potential difference of 14.0 V between them. (a) Determine the capacitance of the system. F (b) What is the potential difference between the two conductors if the charges on each are increased to +196.0 µC and -196.0 µC? Varrow_forwardPlease see the attached image and answer the set of questions with proof.arrow_forwardHow, Please type the whole transcript correctly using comma and periods as needed. I have uploaded the picture of a video on YouTube. Thanks,arrow_forward
- A spectra is a graph that has amplitude on the Y-axis and frequency on the X-axis. A harmonic spectra simply draws a vertical line at each frequency that a harmonic would be produced. The height of the line indicates the amplitude at which that harmonic would be produced. If the Fo of a sound is 125 Hz, please sketch a spectra (amplitude on the Y axis, frequency on the X axis) of the harmonic series up to the 4th harmonic. Include actual values on Y and X axis.arrow_forwardSketch a sign wave depicting 3 seconds of wave activity for a 5 Hz tone.arrow_forwardSketch a sine wave depicting 3 seconds of wave activity for a 5 Hz tone.arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningUniversity Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College





