Explanation Given: Each week at a furniture factory, 2000 work hours are available in the construction department, 1400 work hours in the painting department, and 1300 work hours in the packing department. Producing a chair requires 2 hours of construction, 1 hour of painting, and 2 hours for packing. Producing a table requires 4 hours of construction, 3 hours of painting, and 3 hours for packing. Producing a chest requires 8 hours of construction, 6 hours of painting, and 4 hours for packing. Formula used: Calculation: Let x number of chairs can be made, y number of tables can be made, and z chest can be made. Since there are 2000 work hours available in the construction department. Then, 2 x + 4 y + 8 z = 2000 x + 2 y + 4 z = 1000 So, x + 2 y + 4 z = 1000 …...…... (1) Since there are 1400 work hours available in the painting department. Then, x + 3 y + 6 z = 1400 …...…... (2) Since there are 1300 work hours available in the packing department. Then, 2 x + 3 y + 4 z = 1300 …...…... (3) Now, subtract equation (2) from (1). ( x + 2 y + 4 z ) − ( x + 3 y + 6 z ) = 1000 − 1400 − y − 2 z = − 400 y + 2 z = 400 So, y + 2 z = 400 …...…... (4) Now, multiply equation (2) by 2 and subtract from (3)

Mathematics with Applications In the Management, Natural, and Social Sciences Plus NEW MyLab Math with Pearson eText -- Access Card Package (11th Edition)

11th Edition

ISBN: 9780321935441

Author: Margaret L. Lial, Thomas W. Hungerford, John P. Holcomb, Bernadette Mullins

Publisher: PEARSON

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Chapter 6, Problem 20RE

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To calculate: The number of chair, table, chest can be made.

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Chapter 6, Problem 19RE

Chapter 6, Problem 21RE

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Mathematics with Applications In the Management, Natural, and Social Sciences Plus NEW MyLab Math with Pearson eText -- Access Card Package (11th Edition)

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