Principles of Information Systems
13th Edition
ISBN: 9781337660556
Author: Ralph Stair; George Reynolds
Publisher: Cengage Learning US
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Expert Solution & Answer
Chapter 6, Problem 1SAT
Program Description Answer
Communication media can be divided into two board categories “guided and wireless”.
Hence, the correct answer is option “D”.
Expert Solution & Answer
Explanation of Solution
Communication media:
- Communication media refers to delivering and receiving data or information.
- Transmission and storage tools or channels for data storage and transmission fall under telecommunication.
- The transmission media can be divided into two categories guided transmission media and wireless transmission media.
- The communications signals are guided along a solid medium in the guide transmission media. For example, twisted-pair wire, fiber-optic cable, coaxial cable.
- The telecommunication signal is broadcast over airwaves in the wireless transmission media. The major technologies include microwave, infrared and radio.
Explanation for incorrect options:
Infrared and microwave
The infrared and microwave are the example of the wireless telecommunication media.
Hence, the option “A” is wrong.
Fiber optic and cable
The fiber optic and cable are the example of the guided telecommunication media.
Hence, the option “B” is wrong.
Packet switching and circuit switching
Packet switching and circuit switching are not the categories of communication media.
Hence, the option “C” is wrong.
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Given a shared data set, we allow multiple readers to read at the same time, and only one single writer can access the shared data at the same time. In the lecture slides, a solution is given. However, the problem is that the write cannot write forever, if there are always at least one reader.
How to ensure that the writer can eventually write? Propose your solution by using semaphores and implemented in Python
from threading import Thread, Semaphore
from time import sleep
from sys import stdout
class Reader(Thread):
def__init__(self, name):
self.n=name; Thread.__init__(self)
defrun(self):
globalnr, nw, dr, dw
whileTrue:
# ⟨await nw == 0 then nr += 1⟩
e.acquire()
ifnw>0:
#if nw > 0 or dw > 0 :
dr+=1; e.release(); r.acquire()
nr+=1
ifdr>0: dr-=1; r.release()
else: e.release()
# read data
stdout.write(self.n+' reading\n')
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Chapter 6 Solutions
Principles of Information Systems
Ch. 6.1 - Prob. 1RQCh. 6.1 - Prob. 2RQCh. 6.1 - Prob. 1CTQCh. 6.1 - Prob. 2CTQCh. 6.2 - Prob. 1RQCh. 6.2 - Prob. 2RQCh. 6.2 - Prob. 1CTQCh. 6.3 - Prob. 1RQCh. 6.3 - Prob. 2RQCh. 6.3 - Prob. 1CTQ
Ch. 6.3 - Prob. 2CTQCh. 6.4 - Prob. 1RQCh. 6.4 - Prob. 2RQCh. 6.4 - Prob. 1CTQCh. 6.4 - Prob. 2CTQCh. 6 - Prob. 1SATCh. 6 - Prob. 2SATCh. 6 - Prob. 3SATCh. 6 - Prob. 4SATCh. 6 - Prob. 5SATCh. 6 - Prob. 6SATCh. 6 - Prob. 7SATCh. 6 - Prob. 8SATCh. 6 - Prob. 9SATCh. 6 - Prob. 10SATCh. 6 - Prob. 11SATCh. 6 - Prob. 12SATCh. 6 - Prob. 13SATCh. 6 - Prob. 14SATCh. 6 - Prob. 15SATCh. 6 - Prob. 1RQCh. 6 - Prob. 2RQCh. 6 - Prob. 3RQCh. 6 - Prob. 4RQCh. 6 - Prob. 5RQCh. 6 - Prob. 6RQCh. 6 - Prob. 7RQCh. 6 - Prob. 8RQCh. 6 - Prob. 9RQCh. 6 - Prob. 10RQCh. 6 - Prob. 11RQCh. 6 - Prob. 12RQCh. 6 - Prob. 13RQCh. 6 - Prob. 14RQCh. 6 - Prob. 15RQCh. 6 - Prob. 16RQCh. 6 - Prob. 17RQCh. 6 - Prob. 18RQCh. 6 - Prob. 19RQCh. 6 - Prob. 1DQCh. 6 - Prob. 2DQCh. 6 - Prob. 3DQCh. 6 - Prob. 4DQCh. 6 - Prob. 5DQCh. 6 - Prob. 6DQCh. 6 - Prob. 7DQCh. 6 - Prob. 8DQCh. 6 - Prob. 9DQCh. 6 - Prob. 10DQCh. 6 - Prob. 11DQCh. 6 - Prob. 12DQCh. 6 - Prob. 13DQCh. 6 - Prob. 14DQCh. 6 - Prob. 15DQCh. 6 - Prob. 16DQCh. 6 - Prob. 17DQCh. 6 - Prob. 18DQCh. 6 - Prob. 19DQCh. 6 - Prob. 1PSECh. 6 - Prob. 2PSECh. 6 - Prob. 3PSECh. 6 - Prob. 1TACh. 6 - Prob. 2TACh. 6 - Prob. 1WECh. 6 - Prob. 2WECh. 6 - Prob. 3WECh. 6 - Prob. 2CECh. 6 - Prob. 3CECh. 6 - Prob. 1CTQ1Ch. 6 - Prob. 2CTQ1Ch. 6 - Prob. 3CTQ1Ch. 6 - Prob. 1CTQ2Ch. 6 - Prob. 2CTQ2Ch. 6 - Prob. 3CTQ2
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