PROGRAMMABLE LOGIC CONTROLLERS (LOOSE PA
5th Edition
ISBN: 9781264206216
Author: Petruzella
Publisher: MCG
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Chapter 6, Problem 1RQ
Explanation of Solution
Principle of an electromagnetic control relay:
- The working of an electromagnetic control relay is based on the principle of magnetic induction.
- It consists of an electromagnet or coil to switch contacts.
- When the coil is energized, the movable contacts in between the fixed contacts will swing and come in contact with the bottom fixed contact.
- This results in passing current through the coil of the relay.
- On the other hand, if the coil is de-energized, then the movable contact will be detached from the fixed contact and acts as an open circuit.
- Hence, no current will be passed through the relay.
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make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal.
Create 2 groups: marketing and research.
Add Shamir, Jose, and Kate to the marketing group.
Add Don, Liz, and Sal to the research group.
Create a shared directory for each group.
Create two files to put into each directory:
spreadsheetJanuary.txt
meetingNotes.txt
Assign access permissions to the directories:
Groups should have Read+Write access
Leave owner permissions as they are
“Everyone else” should not have any access
Submit for grade:
Screenshot of /etc/passwd contents showing your new users
Screenshot of /etc/group contents showing new groups with their members
Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers,
⚫ your circuit diagrams for your extended full adder, designed in Section 1 and
⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2.
1 An Extended Full Adder
In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj,
Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit
outputs: sj, Cout and rout.
The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA
ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only
on t₁ and to in the first place:
t₁ to Description
00
Output Relationship
Ignored
Inputs
Addition Mode
2 Coutsjaj + bj + Cin, Tout= 0
Tin
0 1
Shift Left Mode
Sj = Cin,
Cout=bj, rout = 0
rin, aj
10
1 1
Shift Right…
Chapter 6 Solutions
PROGRAMMABLE LOGIC CONTROLLERS (LOOSE PA
Ch. 6 - Prob. 1RQCh. 6 - Prob. 2RQCh. 6 - Prob. 3RQCh. 6 - Prob. 4RQCh. 6 - Prob. 5RQCh. 6 - Prob. 6RQCh. 6 - Prob. 7RQCh. 6 - Prob. 8RQCh. 6 - What do the abbreviations NO and NC represent when...Ch. 6 - Prob. 10RQ
Ch. 6 - Prob. 11RQCh. 6 - Prob. 12RQCh. 6 - Compare the operation of a photovoltaic solar cell...Ch. 6 - What are the two basic components of a...Ch. 6 - Prob. 15RQCh. 6 - Give an explanation of how a scanner and a decoder...Ch. 6 - Prob. 17RQCh. 6 - Prob. 18RQCh. 6 - Prob. 19RQCh. 6 - Prob. 20RQCh. 6 - Prob. 21RQCh. 6 - Prob. 22RQCh. 6 - Prob. 23RQCh. 6 - Prob. 24RQCh. 6 - Prob. 25RQCh. 6 - Prob. 26RQCh. 6 - Prob. 27RQCh. 6 - Prob. 28RQCh. 6 - Prob. 29RQCh. 6 - Prob. 30RQCh. 6 - Prob. 31RQCh. 6 - Prob. 32RQCh. 6 - Prob. 33RQCh. 6 - Prob. 1PCh. 6 - Prob. 2PCh. 6 - Prob. 3PCh. 6 - Prob. 4PCh. 6 - Design a PLC program and prepare a typical I/O...Ch. 6 - Prob. 6PCh. 6 - Prob. 7PCh. 6 - Prob. 8P
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